This page details the qualifying process for the 1988 African Cup of Nations in Morocco. Morocco, as hosts, and Egypt, as title holders, qualified automatically.
Qualifying tournament
:'''''' qualified as holders :'''''' qualified as hosts Preliminary round Guinea won 3–1 on aggregate. ---- Uganda won 5–0 on aggregate. ---- Angola won 5–3 on penalty shootout after 1–1 on aggregate. ---- Congo won 7–2 on aggregate. ---- Sierra Leone won 3–2 on aggregate. ---- Tanzania advanced after Ethiopia withdrew. ---- Madagascar advanced after Mauritius withdrew. ---- Rwanda advanced after Lesotho withdrew. ---- Togo advanced after Equatorial Guinea withdrew. ---- Tunisia advanced after Mali withdrew. First round Algeria won 2–1 on aggregate. ---- Kenya won 3–2 on aggregate. ---- Nigeria won 3–1 on aggregate. ---- Cameroon won 6–4 on aggregate. ---- Ivory Coast won 4–1 on aggregate. ---- Zimbabwe won 4–3 on aggregate. ---- Senegal won 4–0 on aggregate. ---- Sudan won 2–1 on aggregate. ---- Zaire won 3–1 on aggregate. ---- Sierra Leone won 2–1 on aggregate. ---- Libya advanced after Zambia withdrew. ---- Malawi advanced after Rwanda withdrew. Second round Ivory Coast won 4–1 on aggregate. ---- Nigeria won 3–2 on aggregate. ---- Cameroon won 2–1 on aggregate. ---- Kenya won by away goals rule after 1–1 on aggregate. ---- Zaire won 4–2 on penalty shootout after 0–0 on aggregate. ---- Algeria advanced after Libya withdrew. ==Qualified teams==