In the 2005–06 Cypriot Cup, participated all the teams of the
Cypriot First Division, the
Cypriot Second Division, the
Cypriot Third Division and 12 of the 14 teams of the
Cypriot Fourth Division. The competition consisted of seven rounds. In the first and in the second round each tie was played as a single leg and was held at the home ground of one of the two teams, according to the draw results. Each tie winner was qualifying to the next round. If a match was drawn,
extra time was following. If extra time was drawn, the winner was decided by
penalty shoot-out. The third round was played in a two-legged format, each team playing a home and an away match against their opponent. The team which scored more goals on aggregate, was qualifying to the next round. If the two teams scored the same number of goals on aggregate, then the team which scored more goals away from home was advancing to the next round. If both teams had scored the same number of home and away goals, then
extra time was following after the end of the second leg match. If during the extra thirty minutes both teams had managed to score, but they had scored the same number of goals, then the team who scored the away goals was advancing to the next round (i.e. the team which was playing away). If there weren't scored any goals during extra time, the qualifying team was determined by
penalty shoot-out. In the next round, the teams were drawn into four groups of four. The teams of each group played against each other twice, once at their home and once away. The group winners and runners-up of each group advanced to the next round. The quarter-finals and semi-finals were played over two legs and the same format as in the third round was applied. The final was a single match. The cup winner secured a place in the
2006–07 UEFA Cup. ==First round==