colored by degree (bright orange/red = 1, green = 2, blue = 3, yellow = 4). The larger points come from polynomials with smaller integer coefficients. • If a polynomial with rational coefficients is multiplied through by the
least common denominator, the resulting polynomial with integer coefficients has the same roots. This shows that an algebraic number can be equivalently defined as a root of a polynomial with either integer or rational coefficients. • Given an algebraic number, there is a unique
monic polynomial with rational coefficients of least
degree that has the number as a root. This polynomial is called its
minimal polynomial. If its minimal polynomial has degree , then the algebraic number is said to be of
degree . For example, all
rational numbers have degree 1, and an algebraic number of degree 2 is a
quadratic irrational. • The algebraic numbers are
dense in the reals. This follows from the fact they contain the rational numbers, which are dense in the reals themselves. • The set of algebraic numbers is countable, and therefore its
Lebesgue measure as a subset of the complex numbers is 0 (essentially, the algebraic numbers take up no space in the complex numbers). That is to say,
"almost all" real and complex numbers are transcendental. • All algebraic numbers are
computable and therefore
definable and
arithmetical. • For real numbers and , the complex number is algebraic if and only if both and are algebraic.
Degree of simple extensions of the rationals as a criterion to algebraicity For any , the
simple extension of the rationals by , denoted by \Q(\alpha) (whose elements are the f(\alpha) for f a
rational function with rational coefficients which is defined at \alpha), is of finite
degree if and only if is an algebraic number. The condition of finite degree means that there is a fixed set of numbers \{a_i\} of finite
cardinality with elements in \Q(\alpha) such that \textstyle \Q(\alpha) = \sum_{i=1}^k a_i \Q; that is, each element of \Q(\alpha) can be written as a sum \textstyle \sum_{i=1}^k a_i q_i for some rational coefficients \{q_i \}. Since the a_i are themselves members of \Q(\alpha), each can be expressed as sums of products of rational numbers and powers of , and therefore this condition is equivalent to the requirement that for some finite n, \Q(\alpha) = \biggl\lbrace \sum_{i=-n}^n \alpha^{i} q_i \mathbin{\bigg|} q_i\in \Q\biggr\rbrace. The latter condition is equivalent to \alpha^{n+1}, itself a member of \Q(\alpha), being expressible as \textstyle \sum_{i=-n}^n \alpha^i q_i for some rationals \{q_i\}, so \textstyle \alpha^{2n+1} = \sum_{i=0}^{2n} \alpha^i q_{i-n} or, equivalently, is a root of \textstyle x^{2n+1}-\sum_{i=0}^{2n} x^i q_{i-n}; that is, an algebraic number with a minimal polynomial of degree not larger than 2n+1. It can similarly be proven that for any finite set of algebraic numbers \alpha_1, \alpha_2... \alpha_n, the field extension \Q(\alpha_1, \alpha_2, ... \alpha_n) has a finite degree. ==Field==