The \alpha\beta\gamma transform applied to three-phase currents, as used by Edith Clarke, is : \begin{bmatrix}i_\alpha(t)\\i_\beta(t)\\i_\gamma(t)\end{bmatrix} = i_{\alpha\beta\gamma}(t) = Ti_{abc}(t) = \frac{2}{3}\begin{bmatrix} 1 & -\frac{1}{2} & -\frac{1}{2} \\ 0 & \frac{\sqrt{3}}{2} & -\frac{\sqrt{3}}{2} \\ \frac{1}{2} & \frac{1}{2} & \frac{1}{2} \\ \end{bmatrix}\begin{bmatrix}i_a(t)\\i_b(t)\\i_c(t)\end{bmatrix} where i_{abc}(t) is a generic three-phase current sequence and i_{\alpha\beta\gamma}(t) is the corresponding current sequence given by the transformation T. The inverse transform is: : \begin{bmatrix}i_a(t)\\i_b(t)\\i_c(t)\end{bmatrix} = i_{abc}(t) = T^{-1}i_{\alpha\beta\gamma}(t) = \begin{bmatrix} 1 & 0 & 1\\ -\frac{1}{2} & \frac{\sqrt{3}}{2} & 1\\ -\frac{1}{2} & -\frac{\sqrt{3}}{2} & 1\end{bmatrix} \begin{bmatrix}i_\alpha(t)\\i_\beta(t)\\i_\gamma(t)\end{bmatrix}. The above Clarke's transformation preserves the amplitude of the electrical variables which it is applied to. Indeed, consider a three-phase symmetric, direct, current sequence : \begin{align} i_a(t)=&\sqrt{2}I\cos\theta(t),\\ i_b(t)=&\sqrt{2}I\cos\left(\theta(t)-\frac23\pi\right),\\ i_c(t)=&\sqrt{2}I\cos\left(\theta(t)+\frac23\pi\right), \end{align} where I is the
RMS of i_a(t), i_b(t), i_c(t) and \theta(t) is the generic time-varying angle that can also be set to \omega t without loss of generality. Then, by applying T to the current sequence, it results : \begin{align} i_{\alpha}=&\sqrt2 I\cos\theta(t),\\ i_{\beta}=&\sqrt2 I\sin\theta(t),\\ i_{\gamma}=&0, \end{align} where the last equation holds since we have considered balanced currents. As it is shown in the above, the amplitudes of the currents in the \alpha\beta\gamma reference frame are the same of that in the natural reference frame.
Power invariant transformation The active and reactive powers computed in the Clarke's domain with the transformation shown above are not the same of those computed in the standard reference frame. This happens because T is not
unitary. In order to preserve the active and reactive powers one has, instead, to consider :i_{\alpha\beta\gamma}(t) = Ui_{abc}(t) = \sqrt{\frac{2}{3}}\begin{bmatrix} 1 & -\frac{1}{2} & -\frac{1}{2} \\ 0 & \frac{\sqrt{3}}{2} & -\frac{\sqrt{3}}{2} \\ \frac{1}{\sqrt2} & \frac{1}{\sqrt2} & \frac{1}{\sqrt2} \\ \end{bmatrix}\begin{bmatrix}i_a(t)\\i_b(t)\\i_c(t)\end{bmatrix}, where U is a (real) unitary matrix and the inverse coincides with its transpose. In this case the amplitudes of the transformed currents are not the same of those in the standard reference frame, that is : \begin{align} i_{\alpha}=&\sqrt3 I\cos\theta(t),\\ i_{\beta}=&\sqrt3 I\sin\theta(t),\\ i_{\gamma}=&0. \end{align} Finally, the inverse transformation in this case is : i_{abc}(t) = \sqrt{\frac{2}{3}}\begin{bmatrix} 1 & 0 & \frac{1}{\sqrt{2}} \\ -\frac{1}{2} & \frac{\sqrt{3}}{2} & \frac{1}{\sqrt{2}} \\ -\frac{1}{2} & -\frac{\sqrt{3}}{2} & \frac{1}{\sqrt{2}} \\ \end{bmatrix}\begin{bmatrix}i_\alpha(t)\\i_\beta(t)\\i_\gamma(t)\end{bmatrix}.
Simplified transformation Since in a balanced system i_a(t)+i_b(t)+i_c(t)=0 and thus i_\gamma(t)=0 one can also consider the simplified transform :\begin{align} i_{\alpha\beta}(t) &= \frac23 \begin{bmatrix} 1 & -\frac12 & -\frac12\\ 0 & \frac{\sqrt{3}}{2} & -\frac{\sqrt{3}}{2} \end{bmatrix}\begin{bmatrix}i_a(t)\\i_b(t)\\i_c(t)\end{bmatrix}\\ &= \begin{bmatrix} 1 & 0\\ \frac{1}{\sqrt{3}} & \frac{2}{\sqrt{3}} \end{bmatrix}\begin{bmatrix}i_a(t)\\i_b(t)\end{bmatrix} \end{align} which is simply the original Clarke's transformation with the 3rd equation excluded, and :i_{abc}(t) = \frac32\begin{bmatrix} \frac23 & 0 \\ -\frac{1}{3} & \frac{\sqrt{3}}{3} \\ -\frac{1}{3} & -\frac{\sqrt{3}}{3} \end{bmatrix} \begin{bmatrix}i_\alpha(t)\\i_\beta(t)\end{bmatrix} which is the corresponding inverse transformation. ==Geometric Interpretation==