A beam deforms and stresses develop inside it when a transverse load is applied on it. In the quasi-static case, the amount of bending
deflection and the stresses that develop are assumed not to change over time. In a horizontal beam supported at the ends and loaded downwards in the middle, the material at the over-side of the beam is compressed while the material at the underside is stretched. There are two forms of internal stresses caused by lateral loads: •
Shear stress parallel to the lateral loading plus complementary shear stress on planes perpendicular to the load direction; • Direct
compressive stress in the upper region of the beam, applicable mostly to cement concreted elements and, • Direct
tensile stress, applicable to steel elements, and is at the lower region of the beam. These last two forces form a
couple or
moment as they are equal in magnitude and opposite in direction. This
bending moment resists the sagging deformation characteristic of a beam experiencing bending. The stress distribution in a beam can be predicted quite accurately when some simplifying assumptions are used. • The beam is subject to
pure bending. This means that the
shear force is zero, and that no torsional or axial loads are present. • The material is
isotropic (or
orthotropic) and
homogeneous. • The material obeys
Hooke's law (it is linearly elastic and will not deform plastically). • The beam is initially straight with a cross section that is constant throughout the beam length. • The beam has an axis of symmetry in the plane of bending. • The proportions of the beam are such that it would fail by bending rather than by crushing, wrinkling or sideways
buckling. • Cross-sections of the beam remain plane during bending. Compressive and tensile forces develop in the direction of the beam axis under bending loads. These forces induce
stresses on the beam. The maximum compressive stress is found at the uppermost edge of the beam while the maximum tensile stress is located at the lower edge of the beam. Since the stresses between these two opposing
maxima vary
linearly, there therefore exists a point on the linear path between them where there is no bending stress. The
locus of these points is the neutral axis. Because of this area with no stress and the adjacent areas with low stress, using uniform cross section beams in bending is not a particularly efficient means of supporting a load as it does not use the full capacity of the beam until it is on the brink of collapse. Wide-flange beams (
-beams) and
truss girders effectively address this inefficiency as they minimize the amount of material in this under-stressed region. The classic formula for determining the bending stress in a beam under simple bending is: :\sigma_x = \frac{M_z y}{I_z} = \frac{M_z}{W_z} where • {\sigma_x} is the bending stress • M_z – the moment about the neutral axis • y – the perpendicular distance to the neutral axis • I_z – the
second moment of area about the neutral axis
z. • W_z - the Resistance Moment about the neutral axis
z. W_z = I_z / y
Extensions of Euler-Bernoulli beam bending theory Plastic bending The equation \sigma = \tfrac{M y}{I_x} is valid only when the stress at the extreme fiber (i.e., the portion of the beam farthest from the neutral axis) is below the
yield stress of the material from which it is constructed. At higher loadings the stress distribution becomes non-linear, and ductile materials will eventually enter a
plastic hinge state where the magnitude of the stress is equal to the yield stress everywhere in the beam, with a discontinuity at the neutral axis where the stress changes from tensile to compressive. This
plastic hinge state is typically used as a
limit state in the design of steel structures.
Complex or asymmetrical bending The equation above is only valid if the cross-section is symmetrical. For homogeneous beams with asymmetrical sections, the maximum bending stress in the beam is given by : \sigma_x(y,z) = - \frac {M_z~I_y + M_y~I_{yz}} {I_y~I_z - I_{yz}^2}y + \frac {M_y~I_z + M_z~I_{yz}} {I_y~I_z - I_{yz}^2}z where y,z are the coordinates of a point on the cross section at which the stress is to be determined as shown to the right, M_y and M_z are the bending moments about the y and z
centroid axes, I_y and I_z are the second moments of area (distinct from moments of inertia) about the y and z axes, and I_{yz} is the
product of moments of area. Using this equation it is possible to calculate the bending stress at any point on the beam cross section regardless of moment orientation or cross-sectional shape. Note that M_y, M_z, I_y, I_z, I_{yz} do not change from one point to another on the cross section.
Large bending deformation For large deformations of the body, the stress in the cross-section is calculated using an extended version of this formula. First the following assumptions must be made: • Assumption of flat sections – before and after deformation the considered section of body remains flat (i.e., is not swirled). • Shear and normal stresses in this section that are perpendicular to the normal vector of cross section have no influence on normal stresses that are parallel to this section. Large bending considerations should be implemented when the bending radius \rho is smaller than ten section heights h: :\rho With those assumptions the stress in large bending is calculated as: : \sigma = \frac {F} {A} + \frac {M} {\rho A} + {\frac {M} {{I_x}'}}y{\frac {\rho}{\rho +y}} where :F is the normal
force :A is the section
area :M is the bending moment :\rho is the local bending radius (the radius of bending at the current section) :{{I_x}'} is the area moment of inertia along the
x-axis, at the y place (see
Steiner's theorem) :y is the position along
y-axis on the section area in which the stress \sigma is calculated. When bending radius \rho approaches infinity and y\ll\rho, the original formula is back: :\sigma = {F \over A} \pm \frac {My}{I} .
Timoshenko bending theory In 1921,
Timoshenko improved upon the Euler–Bernoulli theory of beams by adding the effect of shear into the beam equation. The kinematic assumptions of the Timoshenko theory are: • normals to the axis of the beam remain straight after deformation • there is no change in beam thickness after deformation However, normals to the axis are not required to remain perpendicular to the axis after deformation. The equation for the quasistatic bending of a linear elastic, isotropic, homogeneous beam of constant cross-section beam under these assumptions is : EI~\cfrac{\mathrm{d}^4 w}{\mathrm{d} x^4} = q(x) - \cfrac{EI}{k A G}~\cfrac{\mathrm{d}^2 q}{\mathrm{d} x^2} where I is the
area moment of inertia of the cross-section, A is the cross-sectional area, G is the
shear modulus, k is a
shear correction factor, and q(x) is an applied transverse load. For materials with
Poisson's ratios (\nu) close to 0.3, the shear correction factor for a rectangular cross-section is approximately : k = \cfrac{5 + 5\nu}{6 + 5\nu} The rotation (\varphi(x)) of the normal is described by the equation : \cfrac{\mathrm{d}\varphi}{\mathrm{d}x} = -\cfrac{\mathrm{d}^2w}{\mathrm{d}x^2} -\cfrac{q(x)}{kAG} The bending moment (M) and the shear force (Q) are given by : M(x) = -EI~ \cfrac{\mathrm{d}\varphi}{\mathrm{d}x} ~;~~ Q(x) = kAG\left(\cfrac{\mathrm{d}w}{\mathrm{d}x}-\varphi\right) = -EI~\cfrac{\mathrm{d}^2\varphi}{\mathrm{d}x^2} = \cfrac{\mathrm{d}M}{\mathrm{d}x} == Beams on elastic foundations ==