Chemical and mathematical derivation of Bjerrum plot equations for carbonate system
Suppose that the reactions between
carbon dioxide,
hydrogen ions,
bicarbonate and
carbonate ions, all dissolved in
water, are as follows: Note that reaction is actually the combination of two
elementary reactions: : + H+ + Assuming the
mass action law applies to these two reactions, that water is
abundant, and that the different chemical species are always well-mixed, their
rate equations are : \begin{align} \frac{\textrm{d}\left[\textrm{CO}_2\right]}{\textrm{d}t} &= -k_1\left[\textrm{CO}_2\right] + k_{-1}\left[\textrm{H}^+\right]\left[\textrm{HCO}_3^-\right], \\ \frac{\textrm{d}\left[\textrm{H}^+\right]}{\textrm{d}t} &= k_1\left[\textrm{CO}_2\right] - k_{-1}\left[\textrm{H}^+\right]\left[\textrm{HCO}_3^-\right] + k_2\left[\textrm{HCO}_3^-\right] - k_{-2}\left[\textrm{H}^+\right]\left[\textrm{CO}_3^{2-}\right], \\ \frac{\textrm{d}\left[\textrm{HCO}_3^-\right]}{\textrm{d}t} &= k_1\left[\textrm{CO}_2\right] - k_{-1}\left[\textrm{H}^+\right]\left[\textrm{HCO}_3^-\right] - k_2\left[\textrm{HCO}_3^-\right] + k_{-2}\left[\textrm{H}^+\right]\left[\textrm{CO}_3^{2-}\right], \\ \frac{\textrm{d}\left[\textrm{CO}_3^{2-}\right]}{\textrm{d}t} &= k_2\left[\textrm{HCO}_3^-\right] - k_{-2}\left[\textrm{H}^+\right]\left[\textrm{CO}_3^{2-}\right] \end{align} where denotes
concentration,
t is time, and
K1 and
k−1 are appropriate
proportionality constants for reaction , called respectively the forwards and reverse
rate constants for this reaction. (Similarly
K2 and
k−2 for reaction .) , the concentrations are unchanging, hence the left hand sides of these equations are zero. Then, from the first of these four equations, the ratio of reaction 's rate constants equals the ratio of its equilibrium concentrations, and this ratio, called
K1, is called the
equilibrium constant for reaction , i.e. {{NumBlk|:|K_1 = \frac{k_1}{k_{-1}} = \frac{[\textrm{H}^+]_\text{eq}[\textrm{HCO}_3^-]_\text{eq}}{[\textrm{CO}_2]_\text{eq}}|}} where the subscript 'eq' denotes that these are equilibrium concentrations. Similarly, from the fourth equation for the
equilibrium constant K2 for reaction , {{NumBlk|:|K_2 = \frac{k_2}{k_{-2}} = \frac{\left[\textrm{H}^+\right]_\text{eq}\left[\textrm{CO}_3^{2-}\right]_\text{eq}}{\left[\textrm{HCO}_3^-\right]_\text{eq}}|}} Rearranging gives {{NumBlk|:|\left[\textrm{HCO}_3^-\right]_\text{eq} = \frac{K_1\left[\textrm{CO}_2\right]_\text{eq}}{\left[\textrm{H}^+\right]_\text{eq}} |}} and rearranging , then substituting in , gives {{NumBlk|:|\left[\textrm{CO}_3^{2-}\right]_\text{eq} = \frac{K_2\left[\textrm{HCO}_3^-\right]_\text{eq}}{\left[\textrm{H}^+\right]_\text{eq}} = \frac{K_1 K_2\left[\textrm{CO}_2\right]_\text{eq}}{\left[\textrm{H}^+\right]_\text{eq}^2} |}} The total
concentration of
dissolved inorganic carbon in the system is given by substituting in and : : \begin{align} \textrm{DIC} &= \left[\textrm{CO}_2\right] + \left[\textrm{HCO}_3^-\right] + \left[\textrm{CO}_3^{2-}\right] \\ &= \left[\textrm{CO}_2\right]_\text{eq} \left(1 + \frac{K_1}{\left[\textrm{H}^+\right]_\text{eq}} + \frac{K_1 K_2}{\left[\textrm{H}^+\right]_\text{eq}^2}\right) \\ &= \left[\textrm{CO}_2\right]_\text{eq} \left(\frac{\left[\textrm{H}^+\right]_\text{eq}^2 + K_1\left[\textrm{H}^+\right]_\text{eq} + K_1K_2}{\left[\textrm{H}^+\right]_\text{eq}^2}\right) \end{align} Re-arranging this gives the equation for : : \left[\textrm{CO}_2\right]_\text{eq} = \frac{\left[\textrm{H}^+\right]_\text{eq}^2}{\left[\textrm{H}^+\right]_\text{eq}^2 + K_1\left[\textrm{H}^+\right]_\text{eq} + K_1 K_2} \times \textrm{DIC} The equations for and are obtained by substituting this into and . == See also ==