The Bohr model gives almost exact results only for a system where two charged points orbit each other at speeds much less than that of light. This not only involves one-electron systems such as the
hydrogen atom, singly ionized
helium, and doubly ionized
lithium, but it includes
positronium and
Rydberg states of any atom where one electron is far away from everything else. It can be used for
K-line X-ray transition calculations if other assumptions are added (see
Moseley's law below). In high energy physics, it can be used to calculate the masses of
heavy quark mesons. Calculation of the orbits requires two assumptions. •
Classical mechanics • : The electron is held in a
circular orbit by electrostatic attraction. The
centripetal force is equal to the
Coulomb force. • :: \frac{m_\mathrm{e} v^2}{r} = \frac{Zk_\mathrm{e} e^2}{r^2}, • : where
me is the electron's mass,
e is the
elementary charge,
ke is the
Coulomb constant and
Z is the atom's
atomic number. It is assumed here that the mass of the nucleus is much larger than the electron mass (which is a good assumption). This equation determines the electron's speed at any radius: • :: v = \sqrt{\frac{Zk_\mathrm{e} e^2}{m_\mathrm{e} r}}. • : It also determines the electron's total energy at any radius: • :: E = -\frac{1}{2} m_\mathrm{e} v^2. • : The total energy is negative and inversely proportional to
r. This means that it takes energy to pull the orbiting electron away from the proton. For infinite values of
r, the energy is zero, corresponding to a motionless electron infinitely far from the proton. The total energy is half the
potential energy, the difference being the kinetic energy of the electron. This is also true for noncircular orbits by the
virial theorem. •
A quantum rule • : The
angular momentum is an integer multiple of
ħ: • :: m_\mathrm{e} v r = n \hbar.
Derivation In classical mechanics, if an electron is orbiting around an atom with period T, and if its coupling to the electromagnetic field is weak, so that the orbit doesn't decay very much in one cycle, it will emit electromagnetic radiation in a pattern repeating at every period, so that the Fourier transform of the pattern will only have frequencies which are multiples of 1/T. However, in quantum mechanics, the quantization of angular momentum leads to discrete energy levels of the orbits, and the emitted frequencies are quantized according to the energy differences between these levels. This discrete nature of energy levels introduces a fundamental departure from the classical radiation law, giving rise to distinct spectral lines in the emitted radiation. Bohr assumes that the electron is circling the nucleus in an elliptical orbit obeying the rules of classical mechanics, but with no loss of radiation due to the
Larmor formula. Denoting the total energy as
E, the electron charge as −
e, the nucleus charge as , the electron mass as
me, half the major axis of the ellipse as
a, he starts with these equations: The combination of natural constants in the energy formula is called the Rydberg energy (
RE): : R_\mathrm{E} = \frac{ (k_\mathrm{e} e^2)^2 m_\mathrm{e}}{2 \hbar^2}. This expression is clarified by interpreting it in combinations that form more
natural units: : m_\mathrm{e} c^2 is the
rest mass energy of the electron (511 keV), : \frac{k_\mathrm{e} e^2}{\hbar c} = \alpha \approx \frac{1}{137} is the
fine-structure constant, : R_\mathrm{E} = \frac{1}{2} (m_\mathrm{e} c^2) \alpha^2. Since this derivation is with the assumption that the nucleus is orbited by one electron, we can generalize this result by letting the nucleus have a charge , where
Z is the atomic number. This will now give us energy levels for hydrogenic (hydrogen-like) atoms, which can serve as a rough order-of-magnitude approximation of the actual energy levels. So for nuclei with
Z protons, the energy levels are (to a rough approximation): : E_n = -\frac{Z^2 R_\mathrm{E}}{n^2}. The actual energy levels cannot be solved analytically for more than one electron (see
n-body problem) because the electrons are not only affected by the
nucleus but also interact with each other via the
Coulomb force. When
Z = 1/
α (), the motion becomes highly relativistic, and 2 cancels the
α2 in
R; the orbit energy begins to be comparable to rest energy. Sufficiently large nuclei, if they were stable, would reduce their charge by creating a bound electron from the vacuum, ejecting the positron to infinity. This is the theoretical phenomenon of electromagnetic charge screening which predicts a maximum nuclear charge. Emission of such positrons has been observed in the collisions of heavy ions to create temporary super-heavy nuclei. The Bohr formula properly uses the
reduced mass of electron and proton in all situations, instead of the mass of the electron, : m_\text{red} = \frac{m_\mathrm{e} m_\mathrm{p}}{m_\mathrm{e} + m_\mathrm{p}} = m_\mathrm{e} \frac{1}{1 + m_\mathrm{e}/m_\mathrm{p}}. However, these numbers are very nearly the same, due to the much larger mass of the proton, about 1836.1 times the mass of the electron, so that the reduced mass in the system is the mass of the electron multiplied by the constant . This fact was historically important in convincing Rutherford of the importance of Bohr's model, for it explained the fact that the frequencies of lines in the spectra for singly ionized helium do not differ from those of hydrogen by a factor of exactly 4, but rather by 4 times the ratio of the reduced mass for the hydrogen vs. the helium systems, which was much closer to the experimental ratio than exactly 4. For positronium, the formula uses the reduced mass also, but in this case, it is exactly the electron mass divided by 2. For any value of the radius, the electron and the positron are each moving at half the speed around their common center of mass, and each has only one fourth the kinetic energy. The total kinetic energy is half what it would be for a single electron moving around a heavy nucleus. : E_n = \frac{R_\mathrm{E}}{2 n^2} (positronium). == Rydberg formula ==