The phases of the clean Bose–Hubbard model can be described using a
mean-field Hamiltonian:\begin{align} H_{\textrm{MF}}&=\sum_i \left[ -\mu \hat{n}_i +\frac{U}{2} \hat{n}_i(\hat{n}_i-1)-zt(\psi^{*} \hat{b}_i +\psi\hat{b}^{\dagger}_i)+zt\psi^{*}\psi \right] \end{align}where z is the lattice
co-ordination number. This can be obtained from the full Bose–Hubbard Hamiltonian by setting \hat{b}_{i} \rightarrow \psi+\delta \hat{b} where \psi=\langle \hat{b}_{i} \rangle, neglecting terms quadratic in \delta \hat{b}_{i} (assumedly infinitesimal) and relabelling \delta \hat{b}_{i} \rightarrow \hat{b}_{i}. Because this decoupling breaks the U(1) symmetry of the initial Hamiltonian for all non-zero values of \psi, this parameter acts as a
superfluid order parameter. For simplicity, this decoupling assumes \psi to be the same on every site, which precludes exotic phases such as
supersolids or other inhomogeneous phases. (Other decouplings are possible.) The
phase diagram can be determined by calculating the energy of this mean-field Hamiltonian using second-order
perturbation theory and finding the condition for which \psi \neq 0. To do this, the Hamiltonian is written as a site-local piece plus a perturbation:H_{\textrm{MF}}=\sum_{i}\left[ h^{(0)}_{i}-zt(\psi^{*} \hat{b}_i +\psi\hat{b}^{\dagger}_i) \right] \quad \textrm{with} \quad h^{(0)}_i=-\mu \hat{n}_i +\frac{U}{2} \hat{n}_i(\hat{n}_i-1)+zt\psi^{*}\psiwhere the bilinear terms \psi^{*}\hat{b}_i and its conjugate are treated as the perturbation. The order parameter \psi is assumed to be small near the
phase transition. The local term is diagonal in the
Fock basis, giving the zeroth-order energy contribution:E^{(0)}_m=-\mu m + \frac{U}{2}m(m-1)+zt |\psi|^{2}where m is an integer that labels the filling of the Fock state. The perturbative piece can be treated with second-order perturbation theory, which leads to:E^{(2)}_m=zt |\psi|^2 \sum_{n \neq m} \frac{|\langle m|(\hat{b}_{i}^{\dagger}+\hat{b}_{i})|n \rangle|^2}{E^{(0)}_n-E^{(0)}_m} =-(zt)^2 |\psi|^{2} \left( \frac{m}{U(m-1)-\mu} + \frac{m+1}{\mu-U m} \right).The energy can be expressed as a series expansion in even powers of the order parameter (also known as the
Landau formalism):E=\text{constant} + R |\psi|^2 + W |\psi|^4 +...After doing so, the condition for the mean-field, second-order phase transition between the Mott insulator and the superfluid phase is given by:r=\frac{R}{zt}=1+zt \left( \frac{m}{U(m-1)-\mu} + \frac{m+1}{\mu-U m} \right)=0where the integer m describes the filling of the m^{th} Mott insulating lobe. Plotting the line r=0 for different integer values of m generates the boundary of the different Mott lobes, as shown in the phase diagram. ==Implementation in optical lattices==