Cissoid of Diocles

Let the radius of be . By translation and rotation, we may take to be the origin and the center of the circle to be (a, 0), so is . Then the polar equations of and are: :\begin{align} & r=2a\sec\theta \\ & r=2a\cos\theta . \end{align} By construction, the distance from the origin to a point on the cissoid is equal to the difference between the distances between the origin and the corresponding points on and . In other words, the polar equation of the cissoid is :r=2a\sec\theta-2a\cos\theta=2a(\sec\theta-\cos\theta). Applying some trigonometric identities, this is equivalent to :r=2a\sin^2\!\theta\mathbin/\cos\theta=2a\sin\theta\tan\theta . Let in the above equation. Then :\begin{align} & x = r\cos\theta = 2a\sin^2\!\theta = \frac{2a\tan^2\!\theta}{\sec^2\!\theta} = \frac{2at^2}{1+t^2} \\ & y = tx = \frac{2at^3}{1+t^2} \end{align} are parametric equations for the cissoid. Converting the polar form to Cartesian coordinates produces :(x^2+y^2)x=2ay^2 Construction by double projection A compass-and-straightedge construction of various points on the cissoid proceeds as follows. Given a line and a point not on , construct the line through parallel to . Choose a variable point on , and construct , the orthogonal projection of on , then , the orthogonal projection of on . Then the cissoid is the locus of points . To see this, let be the origin and the line as above. Let be the point ; then is and the equation of the line is . The line through perpendicular to is :t(y-2at)+x=0. To find the point of intersection , set in this equation to get :\begin{align} & t(tx-2at)+x=0,\ x(t^2+1)=2at^2,\ x=\frac{2at^2}{t^2+1} \\ & y=tx=\frac{2at^3}{t^2+1} \end{align} which are the parametric equations given above. While this construction produces arbitrarily many points on the cissoid, it cannot trace any continuous segment of the curve. Newton's construction The following construction was given by Isaac Newton. Let be a line and a point not on . Let be a right angle which moves so that equals the distance from to and remains on , while the other leg slides along . Then the midpoint of describes the curve. To see this, let the distance between and be . By translation and rotation, take and the line . Let and let be the angle between and the -axis; this is equal to the angle between and . By construction, , so the distance from to is . In other words . Also, is the -coordinate of if it is rotated by angle , so . After simplification, this produces parametric equations :x=a(1-\sin\psi),\,y=a\frac{(1-\sin\psi)^2}{\cos\psi}. Change parameters by replacing with its complement to get :x=a(1-\cos\psi),\,y=a\frac{(1-\cos\psi)^2}{\sin\psi} or, applying double angle formulas, :x=2a\sin^2{\psi \over 2},\,y=a\frac{4\sin^4{\psi \over 2}}{2\sin{\psi \over 2}\cos{\psi \over 2}} = 2a\frac{\sin^3{\psi \over 2}}{\cos{\psi \over 2}}. But this is polar equation :r=2a\frac{\sin^2\theta}{\cos\theta} given above with . Note that, as with the double projection construction, this can be adapted to produce a mechanical device that generates the curve. ==Delian problem==

The Greek geometer Diocles used the cissoid to obtain two mean proportionals to a given ratio. This means that given lengths and , the curve can be used to find and so that is to as is to as is to , i.e. , as discovered by Hippocrates of Chios. As a special case, this can be used to solve the Delian problem: how much must the length of a cube be increased in order to double its volume? Specifically, if is the side of a cube, and , then the volume of a cube of side is :u^3=a^3\left(\frac{u}{a}\right)^3=a^3\left(\frac{u}{a}\right)\left(\frac{v}{u}\right)\left(\frac{b}{v}\right)=a^3\left(\frac{b}{a}\right)=2a^3 so is the side of a cube with double the volume of the original cube. Note however that this solution does not fall within the rules of compass and straightedge construction since it relies on the existence of the cissoid. Let and be given. It is required to find so that , giving and as the mean proportionals. Let the cissoid :(x^2+y^2)x=2ay^2 be constructed as above, with the origin, the point , and the line , also as given above. Let be the point of intersection of with . From the given length , mark on so that . Draw and let be the point where it intersects the cissoid. Draw and let it intersect at . Then is the required length. To see this, rewrite the equation of the curve as :y^2=\frac{x^3}{2a-x} and let , so is the perpendicular to through . From the equation of the curve, :\overline{PN}^2=\frac{\overline{ON}^3}{\overline{NA}}. From this, :\frac{\overline{PN}^3}{\overline{ON}^3}=\frac{\overline{PN}}{\overline{NA}}. By similar triangles and . So the equation becomes :\frac{\overline{UC}^3}{\overline{OC}^3}=\frac{\overline{BC}}{\overline{CA}}, so :\frac{u^3}{a^3}=\frac{b}{a},\, u^3=a^2b as required. Diocles did not really solve the Delian problem. The reason is that the cissoid of Diocles cannot be constructed perfectly, at least not with compass and straightedge. To construct the cissoid of Diocles, one would construct a finite number of its individual points, then connect all these points to form a curve. (An example of this construction is shown on the right.) The problem is that there is no well-defined way to connect the points. If they are connected by line segments, then the construction will be well-defined, but it will not be an exact cissoid of Diocles, but only an approximation. Likewise, if the dots are connected with circular arcs, the construction will be well-defined, but incorrect. Or one could simply draw a curve directly, trying to eyeball the shape of the curve, but the result would only be imprecise guesswork. Once the finite set of points on the cissoid have been drawn, then line will probably not intersect one of these points exactly, but will pass between them, intersecting the cissoid of Diocles at some point whose exact location has not been constructed, but has only been approximated. An alternative is to keep adding constructed points to the cissoid which get closer and closer to the intersection with line , but the number of steps may very well be infinite, and the Greeks did not recognize approximations as limits of infinite steps (so they were very puzzled by Zeno's paradoxes). One could also construct a cissoid of Diocles by means of a mechanical tool specially designed for that purpose, but this violates the rule of only using compass and straightedge. This rule was established for reasons of logical — axiomatic — consistency. Allowing construction by new tools would be like adding new axioms, but axioms are supposed to be simple and self-evident, but such tools are not. So by the rules of classical, synthetic geometry, Diocles did not solve the Delian problem, which actually can not be solved by such means. ==As a pedal curve==

The pedal curve of a parabola with respect to its vertex is a cissoid of Diocles.{{cite book | author=J. Edwards | title=Differential Calculus ==Inversion==

The cissoid of Diocles can also be defined as the inverse curve of a parabola with the center of inversion at the vertex. To see this, take the parabola to be x = y2, in polar coordinate r\cos\theta = (r\sin \theta)^2 or: :r=\frac{\cos\theta}{\sin^2\!\theta}\,. The inverse curve is thus: :r=\frac{\sin^2\!\theta}{\cos\theta} = \sin\theta \tan\theta, which agrees with the polar equation of the cissoid above. ==References==