Bivariate normal distribution Let
X and
Y each be normally distributed with
correlation coefficient ρ. The cokurtosis terms are :K(X,X,Y,Y) = 1+2\rho^2 :K(X,X,X,Y) = K(X,Y,Y,Y) = 3\rho Since the cokurtosis depends only on ρ, which is already completely determined by the lower-degree
covariance matrix, the cokurtosis of the bivariate normal distribution contains no new information about the distribution. It is a convenient reference, however, for comparing to other distributions.
Nonlinearly correlated normal distributions Let
X be standard normally distributed and
Y be the distribution obtained by setting
X=
Y whenever
X0. In other words,
X and
Y are both standard normally distributed with the property that they are completely correlated for negative values and uncorrelated apart from sign for positive values. The joint probability density function is :f_{X,Y}(x,y) = \frac{e^{-x^2/2}}{\sqrt{2\pi}} \left(H(-x)\delta(x-y) + 2H(x)H(y) \frac{e^{-y^2/2}}{\sqrt{2\pi}}\right) where
H(
x) is the
Heaviside step function and δ(
x) is the
Dirac delta function. The fourth moments are easily calculated by integrating with respect to this density: :K(X,X,Y,Y) = 2 :K(X,X,X,Y) = K(X,Y,Y,Y) = \frac{3}{2}+\frac{2}{\pi} \approx 2.137 It is useful to compare this result to what would have been obtained for an ordinary bivariate normal distribution with the usual linear correlation. From integration with respect to density, we find that the linear correlation coefficient of
X and
Y is :\rho = \frac{1}{2} + \frac{1}{\pi} \approx 0.818 A bivariate normal distribution with this value of ρ would have K(X,X,Y,Y) \approx 2.455 and K(X,X,X,Y) \approx 2.339. Therefore, all of the cokurtosis terms of this distribution with this nonlinear correlation are smaller than what would have been expected from a bivariate normal distribution with ρ=0.818. Note that although
X and
Y are individually standard normally distributed, the distribution of the sum
X+
Y is platykurtic. The standard deviation of the sum is :\sigma_{X+Y} = \sqrt{3 + \frac{2}{\pi}} Inserting that and the individual cokurtosis values into the kurtosis sum formula above, we have :K_{X+Y} = \frac{2\pi(8+15\pi)}{(2+3\pi)^2} \approx 2.654 This can also be computed directly from the probability density function of the sum: :f_{X+Y}(u) = \frac{e^{-u^2/8}}{2\sqrt{2\pi}} H(-u) + \frac{e^{-u^2/4}}{\sqrt{\pi}} \operatorname{erf}\left(\frac{u}{2}\right) H(u) == See also ==