For Pseudo-Euclidean space \mathbb{R}^{p,q}, the
Lie algebra of the conformal group is given by the basis \{M_{\mu\nu}, P_\mu, K_\mu, D\} with the following commutation relations: \begin{align} &[D,K_\mu]= -iK_\mu \,, \\ &[D,P_\mu]= iP_\mu \,, \\ &[K_\mu,P_\nu]=2i (\eta_{\mu\nu}D-M_{\mu\nu}) \,, \\ &[K_\mu, M_{\nu\rho}] = i ( \eta_{\mu\nu} K_{\rho} - \eta_{\mu \rho} K_\nu ) \,, \\ &[P_\rho,M_{\mu\nu}] = i(\eta_{\rho\mu}P_\nu - \eta_{\rho\nu}P_\mu) \,, \\ &[M_{\mu\nu},M_{\rho\sigma}] = i (\eta_{\nu\rho}M_{\mu\sigma} + \eta_{\mu\sigma}M_{\nu\rho} - \eta_{\mu\rho}M_{\nu\sigma} - \eta_{\nu\sigma}M_{\mu\rho})\,, \end{align} and with all other brackets vanishing. Here \eta_{\mu\nu} is the
Minkowski metric. In fact, this Lie algebra is isomorphic to the Lie algebra of the Lorentz group with one more space and one more time dimension, that is, \mathfrak{conf}(p,q) \cong \mathfrak{so}(p+1, q+1). It can be easily checked that the dimensions agree. To exhibit an explicit isomorphism, define \begin{align} &J_{\mu\nu} = M_{\mu\nu} \,, \\ &J_{-1, \mu} = \frac{1}{2}(P_\mu - K_\mu) \,, \\ &J_{0, \mu} = \frac{1}{2}(P_\mu + K_\mu) \,, \\ &J_{-1, 0} = D. \end{align} It can then be shown that the generators J_{ab} with a, b = -1, 0, \cdots, n = p+q obey the
Lorentz algebra relations with metric \tilde \eta_{ab} = \operatorname{diag}(-1, +1, -1, \cdots, -1, +1, \cdots, +1). == Conformal group in two spacetime dimensions ==