Volume that the volume of a cone is a third of a cylinder of equal diameter and height The
volume V of any conic solid, regardless of the shape of its base, is one third of the product of the area of the base A_B and the height h V = \frac{1}{3}A_B h. In modern mathematics, this formula can easily be computed using calculus — if A_B = k \cdot h, where k is a coefficient, the integral \int_0^{h} k x^2 \, dx = \tfrac{1}{3} k h^3 Without using calculus, the formula can be proven by comparing the cone to a pyramid and applying
Cavalieri's principle – specifically, comparing the cone to a (vertically scaled) right square pyramid, which forms one third of a cube. This formula cannot be proven without using such infinitesimal arguments – unlike the 2-dimensional formulae for polyhedral area, though similar to the area of the circle – and hence admitted less rigorous proofs before the advent of calculus, with the ancient Greeks using the
method of exhaustion. This is essentially the content of
Hilbert's third problem – more precisely, not all polyhedral pyramids are
scissors congruent (can be cut apart into finite pieces and rearranged into the other), and thus volume cannot be computed purely by using a decomposition argument.
Center of mass The
center of mass of a conic solid of uniform density lies one-quarter of the way from the center of the base to the vertex, on the straight line joining the two.
Right circular cone Volume For a circular cone with radius r and height h, the base is a circle of area \pi r^2 thus the formula for volume is: V = \frac{1}{3} \pi r^2 h
Slant height The
slant height of a right circular cone is the distance from any point on the
circle of its base to the apex via a line segment along the surface of the cone. It is given by \sqrt{r^2+h^2}, where r is the
radius of the base and h is the height. This can be proved by the
Pythagorean theorem.
Surface area The
lateral surface area of a right circular cone is LSA = \pi r \ell where r is the radius of the circle at the bottom of the cone and \ell is the slant height of the cone.{ The surface area of the bottom circle of a cone is the same as for any circle, \pi r^2. Thus, the total surface area of a right circular cone can be expressed as each of the following: • Radius and height ::\pi r^2+\pi r \sqrt{r^2+h^2} :(the area of the base plus the area of the lateral surface; the term \sqrt{r^2+h^2} is the slant height) ::\pi r \left(r + \sqrt{r^2+h^2}\right) :where r is the radius and h is the height. • Radius and slant height ::\pi r^2+\pi r \ell ::\pi r(r+\ell) :where r is the radius and \ell is the slant height. • Circumference and slant height ::\frac {c^2} {4 \pi} + \frac {c\ell} 2 ::\left(\frac c 2\right)\left(\frac c {2\pi} + \ell\right) :where c is the circumference and \ell is the slant height. • Apex angle and height ::\pi h^2 \tan \frac{\theta}{2} \left(\tan \frac{\theta}{2} + \sec \frac{\theta}{2}\right) ::-\frac{\pi h^2 \sin \frac{\theta}{2}}{\sin \frac{\theta}{2}-1} :where \theta is the apex angle and h is the height.
Circular sector The
circular sector is obtained by unfolding the surface of one nappe of the cone: • radius
R ::R = \sqrt{r^2+h^2} • arc length
L ::L = c = 2\pi r • central angle
φ in radians ::\varphi = \frac{L}{R} = \frac{2\pi r}{\sqrt{r^2+h^2}}
Equation form The surface of a cone can be parameterized as :f(\theta,h) = (h \cos\theta, h \sin\theta, h ), where \theta \in [0,2\pi) is the angle "around" the cone, and h \in \mathbb{R} is the "height" along the cone. A right solid circular cone with height h and aperture 2\theta, whose axis is the z coordinate axis and whose apex is the origin, is described parametrically as :F(s,t,u) = \left(u \tan s \cos t, u \tan s \sin t, u \right) where s,t,u range over [0,\theta), [0,2\pi), and [0,h], respectively. In
implicit form, the same solid is defined by the inequalities :\{ F(x,y,z) \leq 0, z\geq 0, z\leq h\}, where :F(x,y,z) = (x^2 + y^2)(\cos\theta)^2 - z^2 (\sin \theta)^2.\, More generally, a right circular cone with vertex at the origin, axis parallel to the vector d, and aperture 2\theta, is given by the implicit
vector equation F(u) = 0 where :F(u) = (u \cdot d)^2 - (d \cdot d) (u \cdot u) (\cos \theta)^2 :F(u) = u \cdot d - |d| |u| \cos \theta where u=(x,y,z), and u \cdot d denotes the
dot product. == Projective geometry ==