If we incorporate some assumptions about our sample, then an analytical expression can be found for both phase contrast and the phase contrast transfer function. As discussed earlier, when the electron wave passes through a sample, the electron beam interacts with the sample via scattering, and experiences a phase shift. This is represented by the electron wavefunction exiting from the bottom of the sample. This expression assumes that the scattering causes a phase shift (and no amplitude shift). This is called the
Phase Object Approximation. The exit wavefunction Following Wade's notation, which is set by the accelerating voltage. U is the effective potential of the sample, which depends on the atomic potentials within the crystal, represented by V. Within the exit wavefunction, the phase shift is represented by: :\phi(r) = \pi\lambda \int dz' U(r,z') This expression can be further simplified taken into account some more assumptions about the sample. If the sample is considered very thin, and a weak scatterer, so that the phase shift is \tau(r,z) = \tau_o[1 + i\phi(r)]
The phase contrast transfer function Passing through the objective lens incurs a Fourier transform and phase shift. As such, the wavefunction on the back focal plane of the objective lens can be represented by: :I(\theta) = \delta(\theta) + \Phi K(\theta) \theta = the scattering angle between the transmitted electron wave and the scattered electron wave \delta = a
delta function representing the non-scattered, transmitted, electron wave \Phi = the Fourier transform of the wavefunction's phase K(\theta) = the phase shift incurred by the microscope's aberrations, also known as the
Contrast Transfer Function: :K(\theta) = \sin[(2\pi/\lambda)W(\theta)] W(\theta) = -z\theta^2/2 + C_s\theta^4/4 \lambda = the relativistic wavelength of the electron wave, C_s = The
spherical aberration of the objective lens The contrast transfer function can also be given in terms of spatial frequencies, or reciprocal space. With the relationship \theta =\lambda k, the phase contrast transfer function becomes: :K(k) = \sin[(2\pi) W(k)] W(k) = -z\lambda k^2/2 + C_s\lambda^3 k^4/4 z = the defocus of the objective lens (using the convention that underfocus is positive and overfocus is negative), \lambda = the relativistic wavelength of the electron wave, C_s = The
spherical aberration of the objective lens, k = the spatial frequency (units of m−1)
Spherical aberration Spherical aberration is a blurring effect arising when a lens is not able to converge incoming rays at higher angles of incidence to the focus point, but rather focuses them to a point closer to the lens. This will have the effect of spreading an imaged point (which is ideally imaged as a single point in the
gaussian image plane) out over a finite size disc in the image plane. Giving the measure of aberration in a plane normal to the optical axis is called a transversal aberration. The size (radius) of the aberration disc in this plane can be shown to be proportional to the cube of the incident angle (θ) under the small-angle approximation, and that the explicit form in this case is : r_s = C_s\cdot\theta^3\cdot M where C_s is the spherical aberration and M is the magnification, both effectively being constants of the lens settings. One can then go on to note that the difference in refracted angle between an ideal ray and one which suffers from spherical aberration, is : \alpha_s = \arctan\left(\frac{b}{R}\right) -\arctan\left(\frac{b}{R+r_s}\right) where b is the distance from the lens to the gaussian image plane and R is the radial distance from the optical axis to the point on the lens which the ray passed through. Simplifying this further (without applying any approximations) shows that : \alpha_s = \arctan\left(\frac{br_s}{R^2 + Rr_s +b^2}\right) Two approximations can now be applied to proceed further in a straightforward manner. They rely on the assumption that both r_s and R are much smaller than b, which is equivalent to stating that we are considering relatively small angles of incidence and consequently also very small spherical aberrations. Under such an assumption, the two leading terms in the denominator are insignificant, and can be approximated as not contributing. By way of these assumptions we have also implicitly stated that the fraction itself can be considered small, and this results in the elimination of the \arctan() function by way of the small-angle approximation; : \alpha_s \approx \arctan\left(\frac{br_s}{b^2}\right)\approx\frac{br_s}{b^2}=\frac{r_s}{b}=\frac{C_s\cdot\theta^3\cdot M}{b} If the image is considered to be approximately in focus, and the angle of incidence \theta is again considered small, then : \frac{R}{f}\approx\tan\left(\theta\right)\approx\theta ~~ \text{and} ~~ M\approx \frac{b}{f} meaning that an approximate expression for the difference in refracted angle between an ideal ray and one which suffers from spherical aberration, is given by : \alpha_s \approx \frac{C_s\cdot R^3}{f^4}
Defocus As opposed to the spherical aberration, we will proceed by estimating the deviation of a defocused ray from the ideal by stating the longitudinal aberration; a measure of how much a ray deviates from the focal point along the optical axis. Denoting this distance \Delta b, it is possible to show that the difference \alpha_f in refracted angle between rays originating from a focused and defocused object, can be related to the refracted angle as : \sqrt{R^2+b^2}\cdot\sin(\alpha_f)=\Delta b \cdot\sin(\theta' -\alpha_f) where R and b are defined in the same way as they were for spherical aberration. Assuming that \alpha_f (or equivalently that |b\cdot\sin(\alpha_f)| ), we can show that : \sin(\alpha_f)\approx\frac{\Delta b \sin(\theta')}{\sqrt{R^2 +b^2}} = \frac{\Delta b \cdot R}{R^2 +b^2} Since we required \alpha_f to be small, and since \theta being small implies R, we are given an approximation of \alpha_f as : \alpha_f\approx\frac{\Delta b\cdot R}{b^2} From the
thin-lens formula it can be shown that \Delta b / b^2 \approx \Delta f / f^2, yielding a final estimation of the difference in refracted angle between in-focus and off-focus rays as : \alpha_f\approx\frac{\Delta f\cdot R}{f^2} : == Examples ==