The reflectivity of a dielectric mirror is based on the
interference of light reflected from the different layers of a dielectric stack. This is the same principle used in multi-layer
anti-reflection coatings, which are dielectric stacks that have been designed to minimize rather than maximize reflectivity. Simple dielectric mirrors function like one-dimensional
photonic crystals, consisting of a stack of layers with a high
refractive index interleaved with layers of a low refractive index (see diagram). The thicknesses of the layers are chosen such that the path-length differences for reflections from different high-index layers are integer multiples of the wavelength for which the mirror is designed. The reflections from the low-index layers have exactly half a wavelength in path-length difference, but there is a 180° difference in phase shift at a low-to-high index boundary, compared to a high-to-low index boundary, which means that these reflections are also in phase. In the case of a mirror at normal incidence, the layers have a thickness of a quarter wavelength. Other designs have a more complicated structure generally produced by
numerical optimization. In the latter case, the
phase dispersion of the reflected light can also be controlled (a
chirped mirror). In the design of dielectric mirrors, an optical
transfer-matrix method can be used. A well-designed multilayer dielectric coating can provide a
reflectivity of over 99% across the
visible light spectrum. Dielectric mirrors exhibit
retardance as a function of angle of incidence and mirror design. As shown in the
GIF, the transmitted color shifts towards the blue with increasing angle of incidence. Regarding interference in the high-reflective-index n_1 medium, this blueshift is given by the formula :2n_2d_2\cos\left(\theta_2\right)=m\lambda, where m\lambda is any multiple of the transmitted wavelength and \theta_2 is the angle of incidence in the second medium. See
thin-film interference for a derivation. However, there is also interference in the low-refractive-index medium. The best reflectivity will be at :\lambda_\perp/\lambda_\theta=\frac{cos(\theta_2)+cos(\theta_1)}{2}\approx \sqrt{1-\frac{sin^2(\theta)}{n^2}}, where \lambda_\perp is the transmitted wavelength under perpendicular angle of incidence and :n=\sqrt{\frac{2}{n_1^{-2}+n_2^{-2}}}. ==Manufacturing==