The degree of dissociation in
gases is denoted by the symbol , where refers to the percentage of gas molecules which dissociate. Various relationships between and exist depending on the
stoichiometry of the equation. The example of
dinitrogen tetroxide () dissociating to
nitrogen dioxide () will be taken. \ce{N2O4 2NO2} If the initial concentration of dinitrogen tetroxide is 1
mole per
litre, this will decrease by at equilibrium giving, by stoichiometry, moles of . The
equilibrium constant (in terms of pressure) is given by the equation K_p = \frac{p\bigl(\ce{NO2}\bigr)^2}{p \, \ce{N2O4}} where represents the
partial pressure. Hence, through the definition of partial pressure and using to represent the total pressure and to represent the
mole fraction; K_p = \frac{p_T^2 \bigl(x \, \ce{NO2} \bigr)^2}{p_T\cdot x \, \ce{N2O4}} = \frac{p_T \bigl(x \, \ce{NO2} \bigr)^2}{x \, \ce{N2O4}} The total number of moles at equilibrium is , which is equivalent to . Thus, substituting the mole fractions with actual values in term of and simplifying; K_p = \frac{p_T(4\alpha^2)}{(1+\alpha)(1-\alpha)} = \frac{p_T(4\alpha^2)}{1-\alpha^2} This equation is in accordance with
Le Chatelier's principle. will remain constant with temperature. The addition of pressure to the system will increase the value of , so must decrease to keep constant. In fact, increasing the pressure of the equilibrium favours a shift to the left favouring the formation of dinitrogen tetroxide (as on this side of the equilibrium there is less pressure since pressure is proportional to number of moles) hence decreasing the extent of dissociation . ==Acids in aqueous solution==