A
shift or
translation functor on a category
D is an additive automorphism (or for some authors, an auto-
equivalence) \Sigma from
D to
D. It is common to write X[n] =\Sigma^n X for integers
n. A
triangle (
X,
Y,
Z,
u,
v,
w) consists of three objects
X,
Y, and
Z, together with morphisms u\colon X\to Y, v\colon Y \to Z and w\colon Z\to X[1]. Triangles are generally written in the unravelled form: :X \xrightarrow{{} \atop u} Y \xrightarrow{{} \atop v} Z \xrightarrow {{} \atop w} X[1], or :X \xrightarrow{{} \atop u} Y \xrightarrow{{} \atop v} Z \xrightarrow {{} \atop w} for short. A
triangulated category is an
additive category D with a translation functor and a class of triangles, called
exact triangles (or
distinguished triangles), satisfying the following properties (TR 1), (TR 2), (TR 3) and (TR 4). (These axioms are not entirely independent, since (TR 3) can be derived from the others.)
TR 1 • For every object
X, the following triangle is exact: ::X \overset{\text{id}}{\to} X \to 0 \to X[1] • For every morphism u\colon X\to Y, there is an object
Z (called a
cone or
cofiber of the morphism
u) fitting into an exact triangle ::X \xrightarrow{{} \atop u} Y \to Z \to X[1] :The name "cone" comes from the
cone of a map of
chain complexes, which in turn was inspired by the
mapping cone in topology. It follows from the other axioms that an exact triangle (and in particular the object
Z) is determined up to isomorphism by the morphism X\to Y, although not always up to a unique isomorphism. • Every triangle isomorphic to an exact triangle is exact. This means that if ::X \xrightarrow{{} \atop u} Y \xrightarrow{{} \atop v} Z \xrightarrow{{} \atop w} X[1] :is an exact triangle, and f\colon X\to X', g\colon Y\to Y', and h\colon Z\to Z' are isomorphisms, then ::X' \xrightarrow{guf^{-1}} Y'\xrightarrow{hvg^{-1}} Z' \xrightarrow {f[1]wh^{-1}} X'[1] :is also an exact triangle.
TR 2 If :X \xrightarrow{{} \atop u} Y \xrightarrow{{} \atop v} Z \xrightarrow {{} \atop w} X[1] is an exact triangle, then so are the two rotated triangles :Y \xrightarrow{{} \atop v} Z \xrightarrow{{} \atop w} X[1] \xrightarrow{-u[1]} Y[1] and :Z[-1] \xrightarrow{-w[-1]} X \xrightarrow{{} \atop u} Y \xrightarrow{{} \atop v} Z.\ In view of the last triangle, the object
Z[−1] is called a
fiber of the morphism X\to Y. The second rotated triangle has a more complex form when [1] and [-1] are not isomorphisms but only mutually inverse equivalences of categories, since -w[-1] is a morphism from Z[-1] to (X[1])[-1], and to obtain a morphism to [X] one must compose with the natural transformation (X[1])[-1] \xrightarrow{} X. This leads to complex questions about possible axioms one has to impose on the natural transformations making [1] and [-1] into a pair of inverse equivalences. Due to this issue, the assumption that [1] and [-1] are mutually inverse isomorphisms is the usual choice in the definition of a triangulated category.
TR 3 Given two exact triangles and a map between the first morphisms in each triangle, there exists a morphism between the third objects in each of the two triangles that makes
everything commute. That is, in the following diagram (where the two rows are exact triangles and
f and
g are morphisms such that
gu =
u′f), there exists a map
h (not necessarily unique) making all the squares commute: :
TR 4: The octahedral axiom Let u\colon X\to Y and v\colon Y\to Z be morphisms, and consider the composed morphism vu\colon X\to Z. Form exact triangles for each of these three morphisms according to TR 1. The octahedral axiom states (roughly) that the three mapping cones can be made into the vertices of an exact triangle so that "everything commutes." More formally, given exact triangles :X \xrightarrow{u\,} Y \xrightarrow{j} Z' \xrightarrow {k} X[1] :Y \xrightarrow{v\,} Z \xrightarrow{l} X' \xrightarrow {i} Y[1] :X \xrightarrow{{} \atop vu} Z \xrightarrow{m} Y' \xrightarrow {n} X[1], there exists an exact triangle :Z' \xrightarrow{f} Y' \xrightarrow{g} X' \xrightarrow {h} Z'[1] such that :l=gm,\quad k=nf,\quad h=j[1]i,\quad ig=u[1]n,\quad fj=mv. This axiom is called the "octahedral axiom" because drawing all the objects and morphisms gives the skeleton of an
octahedron, four of whose faces are exact triangles. The presentation here is Verdier's own, and appears, complete with octahedral diagram, in . In the following diagram,
u and
v are the given morphisms, and the primed letters are the cones of various maps (chosen so that every exact triangle has an
X, a
Y, and a
Z letter). Various arrows have been marked with [1] to indicate that they are of "degree 1"; e.g. the map from
Z′ to
X is in fact from
Z′ to
X[1]. The octahedral axiom then asserts the existence of maps
f and
g forming an exact triangle, and so that
f and
g form commutative triangles in the other faces that contain them: : Two different pictures appear in ( also present the first one). The first presents the upper and lower pyramids of the above octahedron and asserts that given a lower pyramid, one can fill in an upper pyramid so that the two paths from
Y to
Y′, and from
Y′ to
Y, are equal (this condition is omitted, perhaps erroneously, from Hartshorne's presentation). The triangles marked + are commutative and those marked "d" are exact: : The second diagram is a more innovative presentation. Exact triangles are presented linearly, and the diagram emphasizes the fact that the four triangles in the "octahedron" are connected by a series of maps of triangles, where three triangles (namely, those completing the morphisms from
X to
Y, from
Y to
Z, and from
X to
Z) are given and the existence of the fourth is claimed. One passes between the first two by "pivoting" about
X, to the third by pivoting about
Z, and to the fourth by pivoting about
X′. All enclosures in this diagram are commutative (both trigons and the square) but the other commutative square, expressing the equality of the two paths from
Y′ to
Y, is not evident. All the arrows pointing "off the edge" are degree 1: : This last diagram also illustrates a useful intuitive interpretation of the octahedral axiom. In triangulated categories, triangles play the role of exact sequences, and so it is suggestive to think of these objects as "quotients", Z' = Y/X and Y' = Z/X. In those terms, the existence of the last triangle expresses on the one hand :X' = Z/Y\ (looking at the triangle Y \to Z \to X' \to ), and :X' = Y'/Z' (looking at the triangle Z' \to Y' \to X' \to ). Putting these together, the octahedral axiom asserts the "third isomorphism theorem": :(Z/X)/(Y/X)\cong Z/Y. If the triangulated category is the derived category
D(
A) of an abelian category
A, and
X,
Y,
Z are objects of
A viewed as complexes concentrated in degree 0, and the maps X\to Y and Y\to Z are monomorphisms in
A, then the cones of these morphisms in
D(
A) are actually isomorphic to the quotients above in
A. Finally, formulates the octahedral axiom using a two-dimensional commutative diagram with 4 rows and 4 columns. also give generalizations of the octahedral axiom. ==Properties==