Mooney–Rivlin solid

The Mooney–Rivlin model is a special case of the generalized Rivlin model (also called polynomial hyperelastic model{{cite book : W = \sum_{p,q = 0}^N C_{pq} (\bar{I}_1 - 3)^p~(\bar{I}_2 - 3)^q + \sum_{m = 1}^M \frac{1}{D_m}~(J-1)^{2m} with C_{00} = 0 where C_{pq} are material constants related to the distortional response and D_m are material constants related to the volumetric response. For a compressible Mooney–Rivlin material N = 1, C_{01} = C_2, C_{11} = 0, C_{10} = C_1, M=1 and we have : W = C_{01}~(\bar{I}_2 - 3) + C_{10}~(\bar{I}_1 - 3) + \frac{1}{D_1}~(J-1)^2 If C_{01} = 0 we obtain a neo-Hookean solid, a special case of a Mooney–Rivlin solid. For consistency with linear elasticity in the limit of small strains, it is necessary that : \kappa = 2 / D_1 ~;~~ \mu = 2~(C_{01} + C_{10}) where \kappa is the bulk modulus and \mu is the shear modulus. ==Cauchy stress in terms of strain invariants and deformation tensors==

The Cauchy stress in a compressible hyperelastic material with a stress free reference configuration is given by : \boldsymbol{\sigma} = \cfrac{2}{J}\left[\cfrac{1}{J^{2/3}}\left(\cfrac{\partial{W}}{\partial \bar{I}_1} + \bar{I}_1~\cfrac{\partial{W}}{\partial \bar{I}_2}\right)\boldsymbol{B} - \cfrac{1}{J^{4/3}}~\cfrac{\partial{W}}{\partial \bar{I}_2}~\boldsymbol{B} \cdot\boldsymbol{B} \right] + \left[\cfrac{\partial{W}}{\partial J} - \cfrac{2}{3J}\left(\bar{I}_1~\cfrac{\partial{W}}{\partial \bar{I}_1} + 2~\bar{I}_2~\cfrac{\partial{W}}{\partial \bar{I}_2}\right)\right]~\boldsymbol{I} For a compressible Mooney–Rivlin material, : \cfrac{\partial{W}}{\partial \bar{I}_1} = C_1 ~;~~ \cfrac{\partial{W}}{\partial \bar{I}_2} = C_2 ~;~~ \cfrac{\partial{W}}{\partial J} = \frac{2}{D_1}(J-1) Therefore, the Cauchy stress in a compressible Mooney–Rivlin material is given by : \boldsymbol{\sigma} = \cfrac{2}{J}\left[\cfrac{1}{J^{2/3}}\left(C_1 + \bar{I}_1~C_2\right)\boldsymbol{B} - \cfrac{1}{J^{4/3}}~C_2~\boldsymbol{B} \cdot\boldsymbol{B} \right] + \left[\frac{2}{D_1}(J-1)- \cfrac{2}{3J}\left(C_1\bar{I}_1 + 2C_2\bar{I}_2~\right)\right]\boldsymbol{I} It can be shown, after some algebra, that the pressure is given by : p := -\tfrac{1}{3}\,\text{tr}(\boldsymbol{\sigma}) = -\frac{\partial W}{\partial J} = -\frac{2}{D_1} (J-1) \,. The stress can then be expressed in the form : \boldsymbol{\sigma} =-p~\boldsymbol{I} + \cfrac{1}{J}\left[ \cfrac{2}{J^{2/3}}\left(C_1 + \bar{I}_1~C_2\right)\boldsymbol{B} - \cfrac{2}{J^{4/3}}~C_2~\boldsymbol{B}\cdot\boldsymbol{B} -\cfrac{2}{3}\left(C_1\,\bar{I}_1 + 2C_2\,\bar{I}_2\right)\boldsymbol{I}\right] \,. The above equation is often written using the unimodular tensor \bar{\boldsymbol{B}} = J^{-2/3}\,\boldsymbol{B} : : \boldsymbol{\sigma} = -p~\boldsymbol{I} + \cfrac{1}{J}\left[2\left(C_1 + \bar{I}_1~C_2\right)\bar{\boldsymbol{B}} - 2~C_2~\bar{\boldsymbol{B}}\cdot\bar{\boldsymbol{B}} -\cfrac{2}{3}\left(C_1\,\bar{I}_1 + 2C_2\,\bar{I}_2\right)\boldsymbol{I}\right] \,. For an incompressible Mooney–Rivlin material with J = 1 there holds p = 0 and \bar \boldsymbol B = \boldsymbol B . Thus : \boldsymbol{\sigma} = 2\left(C_1 + I_1~C_2\right)\boldsymbol{B} - 2C_2~\boldsymbol{B}\cdot\boldsymbol{B} -\cfrac{2}{3}\left(C_1\,I_1 + 2C_2\,I_2\right)\boldsymbol{I}\,. Since \det J = 1 the Cayley–Hamilton theorem implies : \boldsymbol{B}^{-1} = \boldsymbol{B}\cdot\boldsymbol{B} - I_1~\boldsymbol{B} + I_2~\boldsymbol{I}. Hence, the Cauchy stress can be expressed as : \boldsymbol{\sigma} = -p^{*}~\boldsymbol{I} + 2 C_1~\boldsymbol{B} - 2C_2~\boldsymbol{B}^{-1} where p^{*} := \tfrac{2}{3}(C_1~I_1 - C_2~I_2). \, ==Cauchy stress in terms of principal stretches==

In terms of the principal stretches, the Cauchy stress differences for an incompressible hyperelastic material are given by : \sigma_{11} - \sigma_{33} = \lambda_1~\cfrac{\partial{W}}{\partial \lambda_1} - \lambda_3~\cfrac{\partial{W}}{\partial \lambda_3} ~;~~ \sigma_{22} - \sigma_{33} = \lambda_2~\cfrac{\partial{W}}{\partial \lambda_2} - \lambda_3~\cfrac{\partial{W}}{\partial \lambda_3} For an incompressible Mooney-Rivlin material, : W = C_1(\lambda_1^2 + \lambda_2 ^2+ \lambda_3 ^2 -3) + C_2(\lambda_1^2 \lambda_2^2 + \lambda_2^2 \lambda_3^2 + \lambda_3^2 \lambda_1^2 -3) ~;~~ \lambda_1\lambda_2\lambda_3 = 1 Therefore, : \lambda_1\cfrac{\partial{W}}{\partial \lambda_1} = 2C_1\lambda_1^2 + 2C_2\lambda_1^2(\lambda_2^2+\lambda_3^2) ~;~~ \lambda_2\cfrac{\partial{W}}{\partial \lambda_2} = 2C_1\lambda_2^2 + 2C_2\lambda_2^2(\lambda_1^2+\lambda_3^2) ~;~~ \lambda_3\cfrac{\partial{W}}{\partial \lambda_3} = 2C_1\lambda_3^2 + 2C_2\lambda_3^2(\lambda_1^2+\lambda_2^2) Since \lambda_1\lambda_2\lambda_3=1. we can write : \begin{align} \lambda_1\cfrac{\partial{W}}{\partial \lambda_1} & = 2C_1\lambda_1^2 + 2C_2\left(\cfrac{1}{\lambda_3^2}+\cfrac{1}{\lambda_2^2}\right) ~;~~ \lambda_2\cfrac{\partial{W}}{\partial \lambda_2} = 2C_1\lambda_2^2 + 2C_2\left(\cfrac{1}{\lambda_3^2}+\cfrac{1}{\lambda_1^2}\right) \\ \lambda_3\cfrac{\partial{W}}{\partial \lambda_3} & = 2C_1\lambda_3^2 + 2C_2\left(\cfrac{1}{\lambda_2^2}+\cfrac{1}{\lambda_1^2}\right) \end{align} Then the expressions for the Cauchy stress differences become : \sigma_{11}-\sigma_{33} = 2C_1(\lambda_1^2-\lambda_3^2) - 2C_2\left(\cfrac{1}{\lambda_1^2}-\cfrac{1}{\lambda_3^2}\right)~;~~ \sigma_{22}-\sigma_{33} = 2C_1(\lambda_2^2-\lambda_3^2) - 2C_2\left(\cfrac{1}{\lambda_2^2}-\cfrac{1}{\lambda_3^2}\right) ==Uniaxial extension==

For the case of an incompressible Mooney–Rivlin material under uniaxial elongation, \lambda_1 = \lambda\, and \lambda_2 = \lambda_3 = 1/\sqrt{\lambda}. Then the true stress (Cauchy stress) differences can be calculated as: : \begin{align} \sigma_{11}-\sigma_{33} & = 2C_1\left(\lambda^2-\cfrac{1}{\lambda}\right) -2C_2\left(\cfrac{1}{\lambda^2} - \lambda\right)\\ \sigma_{22}-\sigma_{33} & = 0 \end{align} Simple tension (1, blue line), neo-Hookean solid(2, red line) and Mooney–Rivlin solid models(3, green line) In the case of simple tension, \sigma_{22} = \sigma_{33} = 0 . Then we can write : \sigma_{11} = \left(2C_1 + \cfrac {2C_2} {\lambda} \right) \left( \lambda^2 - \cfrac{1}{\lambda} \right) In alternative notation, where the Cauchy stress is written as \boldsymbol{T} and the stretch as \alpha, we can write :T_{11} = \left(2C_1 + \frac {2C_2} {\alpha} \right) \left( \alpha^2 - \alpha^{-1} \right) and the engineering stress (force per unit reference area) for an incompressible Mooney–Rivlin material under simple tension can be calculated using T_{11}^{\mathrm{eng}} = T_{11}\alpha_2\alpha_3 = \cfrac{T_{11}}{\alpha} . Hence : T_{11}^{\mathrm{eng}}= \left(2C_1 + \frac {2C_2} {\alpha} \right) \left( \alpha - \alpha^{-2} \right) If we define : T^{*}_{11} := \cfrac{T_{11}^{\mathrm{eng}}}{\alpha - \alpha^{-2}} ~;~~ \beta := \cfrac{1}{\alpha} then : T^{*}_{11} = 2C_1 + 2C_2\beta ~. The slope of the T^{*}_{11} versus \beta line gives the value of C_2 while the intercept with the T^{*}_{11} axis gives the value of C_1. The Mooney–Rivlin solid model usually fits experimental data better than Neo-Hookean solid does, but requires an additional empirical constant. ==Equibiaxial tension==

In the case of equibiaxial tension, the principal stretches are \lambda_1 = \lambda_2 = \lambda. If, in addition, the material is incompressible then \lambda_3 = 1/\lambda^2. The Cauchy stress differences may therefore be expressed as : \sigma_{11}-\sigma_{33} = \sigma_{22}-\sigma_{33} = 2C_1\left(\lambda^2-\cfrac{1}{\lambda^4}\right) - 2C_2\left(\cfrac{1}{\lambda^2} - \lambda^4\right) The equations for equibiaxial tension are equivalent to those governing uniaxial compression. ==Pure shear==

A pure shear deformation can be achieved by applying stretches of the form : \lambda_1 = \lambda ~;~~ \lambda_2 = \cfrac{1}{\lambda} ~;~~ \lambda_3 = 1 The Cauchy stress differences for pure shear may therefore be expressed as : \sigma_{11} - \sigma_{33} = 2C_1(\lambda^2-1) - 2C_2\left(\cfrac{1}{\lambda^2}-1\right) ~;~~ \sigma_{22} - \sigma_{33} = 2C_1\left(\cfrac{1}{\lambda^2} -1\right) - 2C_2(\lambda^2 -1) Therefore : \sigma_{11} - \sigma_{22} = 2(C_1+C_2)\left(\lambda^2 - \cfrac{1}{\lambda^2}\right) For a pure shear deformation : I_1 = \lambda_1^2 + \lambda_2^2 + \lambda_3^2 = \lambda^2 + \cfrac{1}{\lambda^2} + 1 ~;~~ I_2 = \cfrac{1}{\lambda_1^2} + \cfrac{1}{\lambda_2^2} + \cfrac{1}{\lambda_3^2} = \cfrac{1}{\lambda^2} + \lambda^2 + 1 Therefore I_1 = I_2. ==Simple shear==

The deformation gradient for a simple shear deformation has the form : \boldsymbol{F} = \boldsymbol{1} + \gamma~\mathbf{e}_1\otimes\mathbf{e}_2 where \mathbf{e}_1,\mathbf{e}_2 are reference orthonormal basis vectors in the plane of deformation and the shear deformation is given by : \gamma = \lambda - \cfrac{1}{\lambda} ~;~~ \lambda_1 = \lambda ~;~~ \lambda_2 = \cfrac{1}{\lambda} ~;~~ \lambda_3 = 1 In matrix form, the deformation gradient and the left Cauchy-Green deformation tensor may then be expressed as : \boldsymbol{F} = \begin{bmatrix} 1 & \gamma & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{bmatrix} ~;~~ \boldsymbol{B} = \boldsymbol{F}\cdot\boldsymbol{F}^T = \begin{bmatrix} 1+\gamma^2 & \gamma & 0 \\ \gamma & 1 & 0 \\ 0 & 0 & 1 \end{bmatrix} Therefore, : \boldsymbol{B}^{-1} = \begin{bmatrix} 1 & -\gamma & 0 \\ -\gamma & 1+\gamma^2 & 0 \\ 0 & 0 & 1 \end{bmatrix} The Cauchy stress is given by : \boldsymbol{\sigma} = \begin{bmatrix} -p^* +2(C_1-C_2)+2C_1\gamma^2 & 2(C_1+C_2)\gamma & 0 \\ 2(C_1+C_2)\gamma & -p^* + 2(C_1 -C_2) - 2C_2\gamma^2 & 0 \\ 0 & 0 & -p^* + 2(C_1 - C_2) \end{bmatrix} For consistency with linear elasticity, clearly \mu = 2(C_1+C_2) where \mu is the shear modulus. ==Rubber==

Elastic response of rubber-like materials are often modeled based on the Mooney–Rivlin model. The constants C_1,C_2 are determined by fitting the predicted stress from the above equations to the experimental data. The recommended tests are uniaxial tension, equibiaxial compression, equibiaxial tension, uniaxial compression, and for shear, planar tension and planar compression. The two parameter Mooney–Rivlin model is usually valid for strains less than 100%. ==Notes and references==