EXPTIME

In terms of DTIME, {{block indent| \mathsf{EXPTIME} = \bigcup_{k \in \mathbb{N} } \mathsf{ DTIME } \left( 2^{ n^k } \right) . }} == Relationships to other classes ==

It is known that and also, by the time hierarchy theorem and the space hierarchy theorem, that In the above expressions, the symbol ⊆ means "is a subset of", and the symbol ⊊ means "is a strict subset of". so at least one of the first three inclusions and at least one of the last three inclusions must be proper, but it is not known which ones are. It is also known that if P = NP, then EXPTIME NEXPTIME, the class of problems solvable in exponential time by a nondeterministic Turing machine. More precisely, E ≠ NE if and only if there exist sparse languages in NP that are not in P. EXPTIME can be reformulated as the space class APSPACE, the set of all problems that can be solved by an alternating Turing machine in polynomial space. This is one way to see that PSPACE ⊆ EXPTIME, since an alternating Turing machine is at least as powerful as a deterministic Turing machine. ==EXPTIME-complete==

A decision problem is EXPTIME-complete if it is in EXPTIME and every problem in EXPTIME has a polynomial-time many-one reduction to it. In other words, there is a polynomial-time algorithm that transforms instances of one to instances of the other with the same answer. Problems that are EXPTIME-complete might be thought of as the hardest problems in EXPTIME. Notice that although it is unknown whether NP is equal to P, we do know that EXPTIME-complete problems are not in P; it has been proven that these problems cannot be solved in polynomial time, by the time hierarchy theorem. In computability theory, one of the basic undecidable problems is the halting problem: deciding whether a deterministic Turing machine (DTM) halts. One of the most fundamental EXPTIME-complete problems is a simpler version of this, which asks if a DTM halts on a given input in at most k steps. It is in EXPTIME because a trivial simulation requires O(k) time, and the input k is encoded using O(log k) bits which causes exponential number of simulations. It is EXPTIME-complete because, roughly speaking, we can use it to determine if a machine solving an EXPTIME problem accepts in an exponential number of steps; it will not use more. The same problem with the number of steps written in unary is P-complete. Other examples of EXPTIME-complete problems include the problem of evaluating a position in generalized chess, checkers, or Go (with Japanese ko rules). These games have a chance of being EXPTIME-complete because games can last for a number of moves that is exponential in the size of the board. In the Go example, the Japanese ko rule is known to imply EXPTIME-completeness, but it is not known if the American or Chinese rules for the game are EXPTIME-complete (they could range from PSPACE to EXPSPACE). By contrast, generalized games that can last for a number of moves that is polynomial in the size of the board are often PSPACE-complete. The same is true of exponentially long games in which non-repetition is automatic. Succinct circuits Another set of important EXPTIME-complete problems relates to succinct circuits. The idea is that if we can exponentially compress the description of a problem that requires polynomial time, then that compressed problem would require exponential time. As one example, some graphs can be succinctly described by a small Boolean circuit. The circuit has 2n inputs, 1 output and \mathsf{poly}(n) gates, thus requiring \mathsf{poly}(n) bits to describe. The circuit represents a graph with 2^n vertices. For each pair of vertices, if the binary code for the two vertices are put into the circuit, then the output of the circuit states whether the two vertices are connected by an edge. For many naturally occurring P-complete decision problems about graphs, where the graph is expressed in a natural representation such as an adjacency matrix, solving the same problem on a succinct circuit representation is EXPTIME-complete, because the input is exponentially smaller; but this requires nontrivial proof, since succinct circuits can only describe a subclass of graphs. Generically, a Boolean circuit with n inputs and a single output is a succinct representation of a string of 2^n bits, which can be used to describe some other object, such as a graph, a 3-CNF formula, etc. For essentially all known NP-complete problems, the succinct version of it is NEXP-complete. In particular, SUCCINCT 3-SAT is NEXP-complete under polynomial-time reductions. ==References==