The arithmetic operations of \R can be partially extended to \overline\R as follows: :\begin{align}a\pm\infty=\pm\infty+a&=\pm\infty,&a&\neq\mp\infty\\a\cdot(\pm\infty)=\pm\infty\cdot a&=\pm\infty,&a&\in(0,+\infty]\\a\cdot(\pm\infty)=\pm\infty\cdot a&=\mp\infty,&a&\in[-\infty,0)\\\frac{a}{\pm\infty}&=0,&a&\in\mathbb{R}\\\frac{\pm\infty}{a}&=\pm\infty,&a&\in(0,+\infty)\\\frac{\pm\infty}{a}&=\mp\infty,&a&\in(-\infty,0)\end{align} For exponentiation, see . Here, a+\infty means both a+(+\infty) and a-(-\infty), while a-\infty means both a-(+\infty) and a+(-\infty). The expressions \infty-\infty, 0\times(\pm\infty), and \pm\infty/\pm\infty (called
indeterminate forms) are usually left
undefined. These rules are modeled on the laws for
infinite limits. However, in the context of
probability or measure theory, 0\times\pm\infty is often defined as 0. When dealing with both positive and negative extended real numbers, the expression 1/0 is usually left undefined, because, although it is true that for every real nonzero sequence f that
converges to 0, the
reciprocal sequence 1/f is eventually contained in every neighborhood of \{\infty,-\infty\}, it is
not true that the sequence 1/f must itself converge to either -\infty or \infty. Said another way, if a
continuous function f achieves a zero at a certain value x_0, then it need not be the case that 1/f tends to either -\infty or \infty in the limit as x tends to x_0. This is the case for the limits of the
identity function f(x)=x when x tends to 0, and of f(x)=x^2\sin\left(1/x\right) (for the latter function, neither -\infty nor \infty is a limit of 1/f(x), even if only positive values of x are considered). However, in contexts where only non-negative values are considered, it is often convenient to define 1/0=+\infty. For example, when working with
power series, the
radius of convergence of a power series with
coefficients a_n is often defined as the reciprocal of the
limit-supremum of the sequence \left(|a_n|^{1/n}\right). Thus, if one allows 1/0 to take the value +\infty, then one can use this formula regardless of whether the limit-supremum is 0 or not. ==Algebraic properties==