The proof of Proposition 1.16 given by Euclid is often cited as one place where Euclid gives a flawed proof. Euclid proves the exterior angle theorem by: •
construct the midpoint E of segment AC, • draw the
ray BE, • construct the point F on ray BE so that E is (also) the midpoint of B and F, • draw the segment FC. By
congruent triangles we can conclude that ∠ BAC = ∠ ECF and ∠ ECF is smaller than ∠ ECD, ∠ ECD = ∠ ACD therefore ∠ BAC is smaller than ∠ ACD and the same can be done for the angle ∠ CBA by bisecting BC. The flaw lies in the assumption that a point (F, above) lies "inside" angle (∠ ACD). No reason is given for this assertion, but the accompanying diagram makes it look like a true statement. When a complete set of axioms for Euclidean geometry is used (see
Foundations of geometry) this assertion of Euclid can be proved.
Invalidity in spherical geometry The exterior angle theorem is not valid in
spherical geometry nor in the related
elliptical geometry. Consider a
spherical triangle one of whose vertices is the
North Pole and the other two lie on the
equator. The sides of the triangle emanating from the North Pole (
great circles of the sphere) both meet the equator at right angles, so this triangle has an exterior angle that is equal to a remote interior angle. The other interior angle (at the North Pole) can be made larger than 90°, further emphasizing the failure of this statement. However, since the Euclid's exterior angle theorem is a theorem in
absolute geometry it is automatically valid in
hyperbolic geometry. == High school exterior angle theorem ==