It will be instructive to consider in some detail a few simple examples. Consider the famous
Schwarzschild vacuum that models spacetime outside an isolated nonspinning spherically symmetric massive object, such as a star. In most textbooks one finds the metric tensor written in terms of a static polar spherical chart, as follows: :ds^2 = -(1-2m/r) \, dt^2 + \frac{dr^2}{1-2m/r} + r^2 \, \left( d\theta^2 + \sin(\theta)^2 \, d\phi^2 \right) : -\infty More formally, the metric tensor can be expanded with respect to the coordinate cobasis as :g = -(1-2m/r) \, dt \otimes dt + \frac{1}{1-2m/r} \, dr \otimes dr + r^2 \, d\theta \otimes d\theta + r^2 \sin(\theta)^2 \, d\phi \otimes d\phi A coframe can be read off from this expression: : \sigma^0 = \sqrt{1-2m/r} \, dt, \; \sigma^1 = \frac{dr}{\sqrt{1-2m/r}}, \; \sigma^2 = r d\theta, \; \sigma^3 = r \sin(\theta) d\phi To see that this coframe really does correspond to the Schwarzschild metric tensor, just plug this coframe into :g = -\sigma^0 \otimes \sigma^0 + \sigma^1 \otimes \sigma^1 + \sigma^2 \otimes \sigma^2 + \sigma^3 \otimes \sigma^3 The frame dual is the coframe inverse as below: (frame dual is also transposed to keep local index in same position.) : \vec{e}_0 = \frac{1}{\sqrt{1-2m/r}} \partial_t, \; \vec{e}_1 = \sqrt{1-2m/r} \partial_r, \; \vec{e}_2 = \frac{1}{r} \partial_\theta, \; \vec{e}_3 = \frac{1}{r \sin(\theta)} \partial_\phi (The plus sign on \sigma^0 ensures that \vec{e}_0 is
future pointing.) This is the frame that models the experience of
static observers who use rocket engines to
"hover" over the massive object. The thrust they require to maintain their position is given by the magnitude of the acceleration vector : \nabla_{\vec{e}_0} \vec{e}_0 = -\frac{m/r^2}{\sqrt{1-2m/r}} \, \vec{e}_1 This is radially inward pointing, since the observers need to accelerate
away from the object to avoid falling toward it. On the other hand, the spatially projected Fermi derivatives of the spatial basis vectors (with respect to \vec{e}_0) vanish, so this is a nonspinning frame. The components of various tensorial quantities with respect to our frame and its dual coframe can now be computed. For example, the
tidal tensor for our static observers is defined using tensor notation (for a coordinate basis) as : E[X]_{ab} = R_{ambn} \, X^m \, X^n where we write \vec{X} = \vec{e}_0 to avoid cluttering the notation. Its only non-zero components with respect to our coframe turn out to be : E[X]_{11} = -2m/r^3, \; E[X]_{22} = E[X]_{33} = m/r^3 The corresponding coordinate basis components are : E[X]_{rr} = -2m/r^3/(1-2m/r), \; E[X]_{\theta \theta} = m/r, \; E[X]_{\phi \phi} = m \sin(\theta)^2/r (A quick note concerning notation: many authors put
carets over
abstract indices referring to a frame. When writing down
specific components, it is convenient to denote frame components by 0,1,2,3 and coordinate components by t,r,\theta,\phi. Since an expression like S_{ab} = 36 m/r doesn't make sense as a
tensor equation, there should be no possibility of confusion.) Compare the
tidal tensor \Phi of Newtonian gravity, which is the
traceless part of the
Hessian of the gravitational potential U. Using tensor notation for a
tensor field defined on three-dimensional
euclidean space, this can be written :\Phi_{ij} = U_{,i j} - \frac{1}{3} {U^{,k}}_{,k} \, \eta_{ij} The reader may wish to crank this through (notice that the trace term actually vanishes identically when U is harmonic) and compare results with the following elementary approach: we can compare the gravitational forces on two nearby observers lying on the same radial line: : m/(r+h)^2 - m/r^2 = -2mh/r^3 + 3mh^2/r^4 + O(h^3) Because in discussing tensors we are dealing with
multilinear algebra, we retain only first order terms, so \Phi_{11} = -2m/r^3. Similarly, we can compare the gravitational force on two nearby observers lying on the same sphere r = r_0. Using some elementary trigonometry and the small angle approximation, we find that the force vectors differ by a vector tangent to the sphere which has magnitude : \frac{m}{r_0^2} \, \sin(\theta) \approx \frac{m}{r_0^2} \, \frac{h}{r_0} = \frac{m}{r_0^3} \, h By using the small angle approximation, we have ignored all terms of order O(h^2), so the tangential components are \Phi_{22} = \Phi_{33} = m/r^3. Here, we are referring to the obvious frame obtained from the polar spherical chart for our three-dimensional euclidean space: : \vec{\epsilon}_1 = \partial_r, \; \vec{\epsilon}_2 = \frac{1}{r} \, \partial_\theta, \; \vec{\epsilon}_3 = \frac{1}{r \sin \theta} \, \partial_\phi Plainly, the coordinate components E[X]_{\theta \theta}, \, E[X]_{\phi \phi} computed above don't even scale the right way, so they clearly cannot correspond to what an observer will measure even approximately. (By coincidence, the Newtonian tidal tensor components agree exactly with the relativistic tidal tensor components we wrote out above.) ==Example: Lemaître observers in the Schwarzschild vacuum==