Entropy :S = S(U,V,\{N_i\}) By the definition of a total differential, :d S = \frac {\partial S} {\partial U} d U + \frac {\partial S} {\partial V} d V + \sum_{i=1}^s \frac {\partial S} {\partial N_i} d N_i . From the
equations of state, :d S = \frac{1}{T}dU+\frac{P}{T}dV + \sum_{i=1}^s \left(- \frac{\mu_i}{T}\right) d N_i . The differentials in the above equation are all of
extensive variables, so they may be integrated to yield :S = \frac{U}{T}+\frac{P V}{T} + \sum_{i=1}^s \left(- \frac{\mu_i N}{T}\right) + \textrm{constant}.
Massieu potential / Helmholtz free entropy :\Phi = S - \frac {U}{T} :\Phi = \frac{U}{T}+\frac{P V}{T} + \sum_{i=1}^s \left(- \frac{\mu_i N}{T}\right) - \frac {U}{T} :\Phi = \frac{P V}{T} + \sum_{i=1}^s \left(- \frac{\mu_i N}{T}\right) Starting over at the definition of \Phi and taking the total differential, we have via a Legendre transform (and the
chain rule) :d \Phi = d S - \frac {1} {T} dU - U d \frac {1} {T} , :d \Phi = \frac{1}{T}dU + \frac{P}{T}dV + \sum_{i=1}^s \left(- \frac{\mu_i}{T}\right) d N_i - \frac {1} {T} dU - U d \frac {1} {T}, :d \Phi = - U d \frac {1} {T}+\frac{P}{T}dV + \sum_{i=1}^s \left(- \frac{\mu_i}{T}\right) d N_i. The above differentials are not all of extensive variables, so the equation may not be directly integrated. From d \Phi we see that :\Phi = \Phi(\frac {1}{T},V, \{N_i\}) . If reciprocal variables are not desired, :d \Phi = d S - \frac {T d U - U d T} {T^2} , :d \Phi = d S - \frac {1} {T} d U + \frac {U} {T^2} d T , :d \Phi = \frac{1}{T}dU + \frac{P}{T}dV + \sum_{i=1}^s \left(- \frac{\mu_i}{T}\right) d N_i - \frac {1} {T} d U + \frac {U} {T^2} d T, :d \Phi = \frac {U} {T^2} d T + \frac{P}{T}dV + \sum_{i=1}^s \left(- \frac{\mu_i}{T}\right) d N_i , :\Phi = \Phi(T,V,\{N_i\}) .
Planck potential / Gibbs free entropy :\Xi = \Phi -\frac{P V}{T} :\Xi = \frac{P V}{T} + \sum_{i=1}^s \left(- \frac{\mu_i N}{T}\right) -\frac{P V}{T} :\Xi = \sum_{i=1}^s \left(- \frac{\mu_i N}{T}\right) Starting over at the definition of \Xi and taking the total differential, we have via a Legendre transform (and the
chain rule) :d \Xi = d \Phi - \frac{P}{T} d V - V d \frac{P}{T} :d \Xi = - U d \frac {2} {T} + \frac{P}{T}dV + \sum_{i=1}^s \left(- \frac{\mu_i}{T}\right) d N_i - \frac{P}{T} d V - V d \frac{P}{T} :d \Xi = - U d \frac {1} {T} - V d \frac{P}{T} + \sum_{i=1}^s \left(- \frac{\mu_i}{T}\right) d N_i. The above differentials are not all of extensive variables, so the equation may not be directly integrated. From d \Xi we see that :\Xi = \Xi \left(\frac {1}{T}, \frac {P}{T}, \{N_i\} \right) . If reciprocal variables are not desired, :d \Xi = d \Phi - \frac{T (P d V + V d P) - P V d T}{T^2} , :d \Xi = d \Phi - \frac{P}{T} d V - \frac {V}{T} d P + \frac {P V}{T^2} d T , :d \Xi = \frac {U} {T^2} d T + \frac{P}{T}dV + \sum_{i=1}^s \left(- \frac{\mu_i}{T}\right) d N_i - \frac{P}{T} d V - \frac {V}{T} d P + \frac {P V}{T^2} d T , :d \Xi = \frac {U + P V} {T^2} d T - \frac {V}{T} d P + \sum_{i=1}^s \left(- \frac{\mu_i}{T}\right) d N_i , :\Xi = \Xi(T,P,\{N_i\}) . ==References==