Let f:=(z-\xi)^{\alpha}\sum_{k=0}^{\infty}c_k(z-\xi)^k be a Frobenius series relative to \xi \in \mathbb{C}. Let Lf=f^{(n)} + q_1f^{(n-1)} + \cdots + q_nf be a linear
differential operator of order n with one valued coefficient functions q_1, \dots, q_n. Let all coefficients q_1,\dots,q_n be expandable as
Laurent series with finite principle part at \xi. Then there exists a smallest N\in\mathbb{N} such that (z-\xi)^Nq_i is a power series for all i\in\{1,\dots, n\}. Hence, Lf is a Frobenius series of the form Lf=(z-\xi)^{\alpha-n-N}\psi(z), with a certain power series \psi(z) in (z-\xi). The
indicial polynomial is defined by P_{\xi}:=\psi(0) which is a polynomial in \alpha, i.e., P_{\xi} equals the coefficient of Lf with lowest degree in (z-\xi). For each formal Frobenius series solution f of Lf=0, \alpha must be a root of the indicial polynomial at \xi, i. e., \alpha needs to solve the
indicial equation P_{\xi}(\alpha) = 0. If \xi is an ordinary point, the resulting indicial equation is given by \alpha^{\underline{n}}=0. If \xi is a
regular singularity, then \deg(P_{\xi}(\alpha))=n and if \xi is an
irregular singularity, \deg(P_{\xi}(\alpha)) holds. This is illustrated by the later examples. The indicial equation relative to \xi=\infty is defined by the indicial equation of \widetilde{L}f, where \widetilde{L} denotes the differential operator L transformed by z=x^{-1}which is a linear differential operator in x, at x=0.
Example: Regular singularity The differential operator of order 2, Lf := f''+\frac{1}{z}f'+\frac{1}{z^2}f, has a regular singularity at z=0. Consider a Frobenius series solution relative to 0, f := z^\alpha(c_0 + c_1z + c_2 z^2 + \cdots) with c_0\neq0. : \begin{align} Lf & = z^{\alpha-2}(\alpha(\alpha-1)c_0 + \cdots) + \frac{1}{z}z^{\alpha-1}(\alpha c_0 + \cdots) + \frac{1}{z^2}z^{\alpha}(c_0 + \cdots) \\[5pt] & = z^{\alpha-2}c_0(\alpha(\alpha-1) + \alpha + 1) + \cdots. \end{align} This implies that the degree of the indicial polynomial relative to 0 is equal to the order of the differential equation, \deg(P_0(\alpha)) = \deg(\alpha^2 + 1) = 2.
Example: Irregular singularity The differential operator of order 2, Lf:=f''+\frac{1}{z^2}f' + f, has an irregular singularity at z=0. Let f be a Frobenius series solution relative to 0. : \begin{align} Lf & = z^{\alpha-2}(\alpha(\alpha-1)c_0 + \cdots) + \frac{1}{z^2}z^{\alpha-1}(\alpha c_0 + (\alpha+1)c_1 z + \cdots) + z^{\alpha}(c_0 + \cdots) \\[5pt] & = z^{\alpha-3} c_0 \alpha + z^{\alpha-2}(c_0\alpha(\alpha-1) + c_1(\alpha+1)) + \cdots. \end{align} Certainly, at least one coefficient of the lower derivatives pushes the exponent of z down. Inevitably, the coefficient of a lower derivative is of smallest exponent. The degree of the indicial polynomial relative to 0 is less than the order of the differential equation, \deg(P_0(\alpha)) = \deg(\alpha) = 1 . == Formal fundamental systems ==