The elements
i,
j, and
k all have
order four in Q8 and any two of them generate the entire group. Another
presentation of Q8 based in only two elements to skip this redundancy is: :\left \langle x,y \mid x^4 = 1, x^2 = y^2, y^{-1}xy = x^{-1} \right \rangle. For instance, writing the group elements in
lexicographically minimal normal forms, one may identify: \{e, \bar e, i, \bar{i}, j, \bar{j}, k, \bar{k}\} \leftrightarrow \{e, x^2, x, x^3, y, x^2 y, xy, x^3 y \}. The quaternion group has the unusual property of being
Hamiltonian: Q8 is non-abelian, but every
subgroup is
normal. Every Hamiltonian group contains a copy of Q8. The quaternion group Q8 and the dihedral group D4 are the two smallest examples of a
nilpotent non-abelian group. The
center and the
commutator subgroup of Q8 is the subgroup \{e,\bar{e}\}. The
inner automorphism group of Q8 is given by the group modulo its center, i.e. the
factor group \mathrm{Q}_8/\{e,\bar{e}\}, which is
isomorphic to the
Klein four-group V. The full
automorphism group of Q8 is
isomorphic to S4, the
symmetric group on four letters (see
Matrix representations below), and the
outer automorphism group of Q8 is thus S4/V, which is isomorphic to S3. The quaternion group Q8 has five conjugacy classes, \{e\}, \{\bar{e}\}, \{i,\bar{i}\}, \{j,\bar{j}\}, \{k,\bar{k}\}, and so five
irreducible representations over the complex numbers, with dimensions 1, 1, 1, 1, 2:
Trivial representation.
Sign representations with i, j, k-kernel: Q8 has three maximal normal subgroups: the cyclic subgroups generated by i, j, and k respectively. For each maximal normal subgroup
N, we obtain a one-dimensional representation factoring through the 2-element
quotient group G/
N. The representation sends elements of
N to 1, and elements outside
N to −1.
2-dimensional representation: Described below in
Matrix representations. It is not
realizable over the real numbers, but is a complex representation: indeed, it is just the quaternions \mathbb{H} considered as an algebra over \mathbb C, and the action is that of left multiplication by Q_8\subset \mathbb H . The
character table of Q8 turns out to be the same as that of D4: Nevertheless, all the irreducible characters \chi_\rho in the rows above have real values, this gives the
decomposition of the real
group algebra of G = \mathrm{Q}_8 into minimal two-sided
ideals: :\R[\mathrm{Q}_8]=\bigoplus_\rho (e_\rho), where the
idempotents e_\rho\in \R[\mathrm{Q}_8] correspond to the irreducibles: :e_\rho = \frac{\dim(\rho)}\sum_{g\in G} \chi_\rho(g^{-1})g, so that :\begin{align} e_{\text{triv}} &= \tfrac 18(e + \bar e + i +\bar i+j+\bar j+k+\bar k) \\ e_{i\text{-ker}} &= \tfrac 18(e + \bar e + i +\bar i-j-\bar j-k-\bar k) \\ e_{j\text{-ker}} &= \tfrac 18(e + \bar e - i -\bar i+j+\bar j-k-\bar k) \\ e_{k\text{-ker}} &= \tfrac 18(e + \bar e - i -\bar i-j-\bar j+k+\bar k) \\ e_{2} &= \tfrac 28(2e - 2\bar e) = \tfrac 12(e - \bar e) \end{align} Each of these irreducible ideals is isomorphic to a real
central simple algebra, the first four to the real field \R. The last ideal (e_2) is isomorphic to the
skew field of
quaternions \mathbb{H} by the correspondence: :\begin{align} \tfrac12(e-\bar e) &\longleftrightarrow 1, \\ \tfrac12(i-\bar i) &\longleftrightarrow i, \\ \tfrac12(j-\bar j) &\longleftrightarrow j, \\ \tfrac12(k-\bar k) &\longleftrightarrow k. \end{align} Furthermore, the projection homomorphism \R[\mathrm{Q}_8]\to (e_2)\cong \mathbb{H} given by r\mapsto re_2 has kernel ideal generated by the idempotent: :e_2^\perp = e_1+e_{i\text{-ker}}+e_{j\text{-ker}}+e_{k\text{-ker}} = \tfrac{1}{2}(e+\bar e), so the quaternions can also be obtained as the
quotient ring \R[\mathrm{Q}_8]/(e+\bar e)\cong \mathbb H. Note that this is irreducible as a real representation of Q_8, but splits into two copies of the two-dimensional irreducible when extended to the complex numbers. Indeed, the complex group algebra is \C[\mathrm{Q}_8] \cong \C^{\oplus 4} \oplus M_2(\C), where M_2(\C) \cong \mathbb{H} \otimes_{\R} \C is the algebra of
biquaternions. == Matrix representations ==