A
free group on a set
S is a group where each element can be
uniquely described as a finite length product of the form: : s_1^{a_1} s_2^{a_2} \cdots s_n^{a_n} where the
si are elements of
S, adjacent
si are distinct, and
ai are non-zero integers (but
n may be zero). In less formal terms, the group consists of words in the generators
and their inverses, subject only to canceling a generator with an adjacent occurrence of its inverse. If
G is any group, and
S is a generating subset of
G, then every element of
G is also of the above form; but in general, these products will not
uniquely describe an element of
G. For example, the
dihedral group D8 of order sixteen can be generated by a rotation
r of order 8 and a flip
f of order 2, and certainly any element of D8 is a product of
rs and
fs. However, we have, for example, , , etc., so such products are
not unique in D8. Each such product equivalence can be expressed as an equality to the identity, such as : , : , or : . Informally, we can consider these products on the left hand side as being elements of the free group , and let . That is, we let
R be the subgroup generated by the strings
rfrf,
r8,
f2, each of which is also equivalent to 1 when considered as products in D8. If we then let
N be the subgroup of
F generated by all conjugates
x−1
Rx of
R, then it follows by definition that every element of
N is a finite product
x1−1
r1
x1 ...
xm−1
rm xm of members of such conjugates. It follows that each element of
N, when considered as a product in D8, will also evaluate to 1; and thus that
N is a normal subgroup of
F. Thus D8 is isomorphic to the
quotient group . We then say that D8 has presentation : \langle r, f \mid r^8 = 1, f^2 = 1, (rf)^2 = 1\rangle. Here the set of generators is , and the set of relations is {{math|1=
R = {
r 8 = 1,
f 2 = 1, (
rf )2 = 1} }}. We often see
R abbreviated, giving the presentation : \langle r, f \mid r^8 = f^2 = (rf)^2 = 1\rangle. An even shorter form drops the equality and identity signs, to list just the set of relators, which is {{math|1= {
r 8,
f 2, (
rf )2} }}. Doing this gives the presentation : \langle r, f \mid r^8, f^2, (rf)^2 \rangle. All three presentations are equivalent. == Notation ==