The
v-topology (or universally subtrusive topology) is equivalent to the
h-topology on the category Sch^{ft}_S of schemes of finite type over a Noetherian base scheme
S. Indeed, a morphism in Sch^{ft}_S is universally subtrusive if and only if it is universally submersive . In other words, Shv_h(Sch^{ft}_S) = Shv_v(Sch^{ft}_S), \qquad (S\ \textrm{Noetherian}) More generally, on the category Sch of all qcqs schemes, neither of the
v- nor the
h- topologies are finer than the other: Shv_h(Sch) \not\subset Shv_v(Sch) and Shv_v(Sch) \not\subset Shv_h(Sch). There are
v-covers which are not
h-covers (e.g., Spec(\mathbb{C}(x)) \to Spec(\mathbb{C}) ) and
h-covers which are not
v-covers (e.g., Spec (R / \mathfrak{p}) \sqcup Spec(R_\mathfrak{p}) \to Spec(R) where
R is a valuation ring of rank 2 and \mathfrak{p} is the non-open, non-closed prime ). However, we could define an
h-analogue of the fpqc topology by saying that an
hqc-covering is a family \{T_i \to T\}_{i \in I} such that for each affine open U \subseteq T there exists a finite set
K, a map i: K \to I and affine opens U_{i(k)} \subseteq T_{i(k)} \times_T U such that \sqcup_{k \in K} U_{i(k)} \to U is universally submersive (with no finiteness conditions). Then every
v-covering is an
hqc-covering. Shv_{hqc}(Sch) \subsetneq Shv_v(Sch). Indeed, any subtrusive morphism is submersive (this is an easy exercise using ). By a theorem of Rydh, for a map f: Y \to X of qcqs schemes with X Noetherian, f is a v-cover if and only if it is an arc-cover (for the statement in this form see ). That is, in the Noetherian setting everything said above for the v-topology is valid for the arc-topology. == Notes ==