The
Laplace transform \mathcal{L} given by :[\mathcal{L}f](s)=\int_0^\infty e^{-st}f(t)dt can be understood as a linear operator :\mathcal{L}:L^2(0,\infty)\to H^2\left(\mathbb{C}^+\right) where L^2(0,\infty) is the set of
square-integrable functions on the positive real number line, and \mathbb{C}^+ is the right half of the complex plane. It is more; it is an
isomorphism, in that it is invertible, and it
isometric, in that it satisfies :\|\mathcal{L}f\|_{H^2} = \sqrt{2\pi} \|f\|_{L^2}. The Laplace transform is "half" of a Fourier transform; from the decomposition :L^2(\mathbb{R})=L^2(-\infty,0) \oplus L^2(0,\infty) one then obtains an
orthogonal decomposition of L^2(\mathbb{R}) into two Hardy spaces :L^2(\mathbb{R})= H^2\left(\mathbb{C}^-\right) \oplus H^2\left(\mathbb{C}^+\right). This is essentially the
Paley-Wiener theorem. == See also==