Haldane approximates the above equation by taking the
continuum limit of the above equation. This is done by multiplying and dividing it by dq so that it is in integral form : dq_n=-Kp_n q_n[\lambda + (1-2 \lambda )q_n ] substituting q=1-p, the cost (given by the total number of deaths, 'D', required to make a substitution) is given by : D = \int_0^{q_{_0}} \frac{[2\lambda + (1 - 2\lambda)q]}{(1 - q)[\lambda + (1 - 2\lambda)q]}dq = \frac{1}{1 - \lambda} \int_0^{q_{_0}} \left[\frac{1}{1 - q} + \frac{\lambda(1 - 2\lambda)}{\lambda + (1 - 2\lambda)q}\right]dq. Assuming λ < 1, this gives : D = \frac{1}{1 - \lambda} \left[-\mbox{ln } p_0 + \lambda \mbox{ ln }\left(\frac{1 - \lambda - (1 - 2\lambda) p_0}{\lambda}\right)\right] \approx \frac{1}{1 - \lambda} \left[-\mbox{ln } p_0 + \lambda \mbox{ ln }\left(\frac{1 - \lambda}{\lambda}\right)\right] where the last approximation assumes p_0 to be small. If λ = 1, then we have : D = \int_0^{q_{_0}} \frac{2 - q}{(1 - q)^2} dq = \int_0^{q_{_0}} \left[\frac{1}{1 - q} + \frac{1}{(1 - q)^2}\right]dq = p_0^{-1} - \mbox{ ln } p_0 + O(\lambda K). In his discussion Haldane writes that the substitution cost, if it is paid by juvenile deaths, "usually involves a number of deaths equal to about 10 or 20 times the number in a generation" – the minimum being the population size (= "the number in a generation") and rarely being 100 times that number. Haldane assumes 30 to be the mean value. Assuming substitution of genes to take place slowly, one gene at a time over
n generations, the fitness of the species will fall below the optimum (achieved when the substitution is complete) by a factor of about 30/
n, so long as this is small – small enough to prevent extinction. Haldane doubts that high intensities – such as in the case of the peppered moth – have occurred frequently and estimates that a value of
n = 300 is a probable number of generations. This gives a selection intensity of I = 30/300 = 0.1. Haldane then continues: The number of loci in a vertebrate species has been estimated at about 40,000. 'Good' species, even when closely related, may differ at several thousand loci, even if the differences at most of them are very slight. But it takes as many deaths, or their equivalents, to replace a gene by one producing a barely distinguishable phenotype as by one producing a very different one. If two species differ at 1000 loci, and the mean rate of gene substitution, as has been suggested, is one per 300 generations, it will take 300,000 generations to generate an interspecific difference. It may take a good deal more, for if an allele a1 is replaced by a10, the population may pass through stages where the commonest genotype is a1a1, a2a2, a3a3, and so on, successively, the various alleles in turn giving maximal fitness in the existing environment and the residual environment. The number 300 of generations is a conservative estimate for a slowly evolving species not at the brink of extinction by Haldane's calculation. For a difference of at least 1,000 genes, 300,000 generations might be needed – maybe more, if some gene runs through more than one optimisation. == Origin of the term "Haldane's dilemma" ==