An exponential decay can be described by any of the following four equivalent formulas:
Half-life and reaction orders In
chemical kinetics, the value of the half-life depends on the
reaction order:
Zero order kinetics The rate of this kind of reaction does not depend on the substrate
concentration, . Thus the concentration decreases linearly. d[\ce A]/dt = - k The integrated
rate law of zero order kinetics is: [\ce A] = [\ce A]_0 - ktIn order to find the half-life, we have to replace the concentration value for the initial concentration divided by 2: [\ce A]_{0}/2 = [\ce A]_0 - kt_{1/2}and isolate the time:t_{1/2} = \frac{[\ce A]_0}{2k}This formula indicates that the half-life for a zero order reaction depends on the initial concentration and the rate constant.
First order kinetics In first order reactions, the rate of reaction will be proportional to the concentration of the reactant. Thus the concentration will decrease exponentially. [\ce A] = [\ce A]_0 \exp(-kt)as time progresses until it reaches zero, and the half-life will be constant, independent of concentration. The time for to decrease from to in a first-order reaction is given by the following equation:[\ce A]_0 /2 = [\ce A]_0 \exp(-kt_{1/2})It can be solved forkt_{1/2} = -\ln \left(\frac{[\ce A]_0 /2}{[\ce A]_0}\right) = -\ln\frac{1}{2} = \ln 2For a first-order reaction, the half-life of a reactant is independent of its initial concentration. Therefore, if the concentration of at some arbitrary stage of the reaction is , then it will have fallen to after a further interval of {{tmath|\tfrac{\ln 2}{k}.}} Hence, the half-life of a first order reaction is given as the following:t_{1/2} = \frac{\ln 2}{k}The half-life of a first order reaction is independent of its initial concentration and depends solely on the reaction rate constant, .
Second order kinetics In second order reactions, the rate of reaction is proportional to the square of the concentration. By integrating this rate, it can be shown that the concentration of the reactant decreases following this formula: \frac{1}{[\ce A]} = kt + \frac{1}{[\ce A]_0} We can set to half the initial concentration and rename to , \frac{2}{[\ce A]_0} = kt_{1/2} + \frac{1}{[\ce A]_0} then rearrange the above to find the half-life of the reactant: t_{1/2} = \frac{1}{[\ce A]_0 k} This shows that the half-life of second order reactions depends on the initial concentration and
rate constant.
Decay by two or more processes Some quantities decay by two exponential-decay processes simultaneously. In this case, the actual half-life can be related to the half-lives and that the quantity would have if each of the decay processes acted in isolation: \frac{1}{T_{1/2}} = \frac{1}{t_1} + \frac{1}{t_2} For three or more processes, the analogous formula is: \frac{1}{T_{1/2}} = \frac{1}{t_1} + \frac{1}{t_2} + \frac{1}{t_3} + \cdots For a proof of these formulas, see
Exponential decay § Decay by two or more processes.
Examples There is a half-life describing any exponential-decay process. For example: • As noted above, in
radioactive decay the half-life is the length of time after which there is a 50% chance that an atom will have undergone
nuclear decay. It varies depending on the atom type and
isotope, and is usually determined experimentally. See
List of nuclides. • The current flowing through an
RC circuit or
RL circuit decays with a half-life of or , respectively. For this example the term
half time tends to be used rather than "half-life", but they mean the same thing. • In a
chemical reaction, the half-life of a species is the time it takes for the concentration of that substance to fall to half of its initial value. In a first-order reaction the half-life of the reactant is , where (also denoted as ) is the
reaction rate constant. ==In non-exponential decay==