Any graph with a nonempty set of edges requires at least two colors; if
G and
H are not 1-colorable, that is, they both contain an edge, then their product also contains an edge, and is hence not 1-colorable either. In particular, the conjecture is true when
G or
H is a bipartite graph, since then its chromatic number is either 1 or 2. Similarly, if two graphs
G and
H are not 2-colorable, that is, not
bipartite, then both contain a cycle of odd length. Since the product of two odd
cycle graphs contains an odd cycle, the product
G ×
H is not 2-colorable either. In other words, if
G ×
H is 2-colorable, then at least one of
G and
H must be 2-colorable as well. The next case was proved long after the conjecture's statement, by : if the product
G ×
H is 3-colorable, then one of
G or
H must also be 3-colorable. In particular, the conjecture is true whenever
G or
H is 4-colorable (since then the inequality χ(
G ×
H) ≤ min {χ(
G), χ(
H)} can only be strict when
G ×
H is 3-colorable). In the remaining cases, both graphs in the tensor product are at least 5-chromatic and progress has only been made for very restricted situations. == Weak Hedetniemi Conjecture ==