Because complex differentiation is linear and obeys the product, quotient, and chain rules, the sums, products and compositions of holomorphic functions are holomorphic, and the quotient of two holomorphic functions is holomorphic wherever the denominator is not zero. That is, if functions and are holomorphic in a domain , then so are , , , and . Furthermore, is holomorphic if has no zeros in ; otherwise it is
meromorphic. If one identifies with the real
plane , then the holomorphic functions coincide with those functions of two real variables with continuous first derivatives which solve the
Cauchy–Riemann equations, a set of two
partial differential equations. Conversely, every harmonic function on a
simply connected domain is the real part of a holomorphic function: If is the harmonic conjugate of , unique up to a constant, then is holomorphic.
Cauchy's integral theorem implies that the
contour integral of every holomorphic function along a
loop vanishes: : \oint_\gamma f(z)\,\mathrm{d}z = 0. Here is a
rectifiable path in a simply connected
complex domain whose start point is equal to its end point, and is a holomorphic function.
Cauchy's integral formula states that every function holomorphic inside a
disk is completely determined by its values on the disk's boundary. Every
holomorphic function is analytic. That is, a holomorphic function has derivatives of every order at each point in its domain, and it coincides with its own
Taylor series at in a neighbourhood of . In fact, coincides with its Taylor series at in any disk centred at that point and lying within the domain of the function. From an algebraic point of view, the set of holomorphic functions on an open set is a
commutative ring and a
complex vector space. Additionally, the set of holomorphic functions in an open set is an
integral domain if and only if the open set is connected. In fact, it is a
locally convex topological vector space, with the
seminorms being the
suprema on
compact subsets. From a geometric perspective, a function is holomorphic at if and only if its
exterior derivative {{tmath|\mathrm{d}f}} in a neighbourhood of is equal to {{tmath| f'(z)\,\mathrm{d}z}} for some continuous function . It follows from : 0 = \mathrm{d}^2 f = \mathrm{d}(f'\,\mathrm{d}z) = \mathrm{d}f' \wedge \mathrm{d}z that {{tmath|\mathrm{d}f'}} is also proportional to {{tmath|\mathrm{d}z}}, implying that the derivative {{tmath|\mathrm{d}f'}} is itself holomorphic and thus that is infinitely differentiable. Similarly, {{tmath|1= \mathrm{d}(f\,\mathrm{d}z ) = f'\,\mathrm{d}z \wedge \mathrm{d}z = 0}} implies that any function that is holomorphic on the simply connected region is also integrable on . For a path from to lying entirely in , define : {{tmath|1= F_\gamma(z) = F(0) + \int_\gamma f\,\mathrm{d}z.}} In light of the
Jordan curve theorem and the
generalized Stokes' theorem, is independent of the particular choice of path , and thus is a well-defined function on having {{tmath|1= \mathrm{d}F = f\,\mathrm{d}z}}, or equivalently {{tmath|1= f = \mathrm{d}F/\mathrm{d}z }}. == Examples ==