Hypercycles in hyperbolic geometry have some properties similar to those of
circles in
Euclidean geometry: •
A line perpendicular to a chord of a hypercycle at its midpoint is a radius and it bisects the arc subtended by the chord. • : Let be the chord and its middle point. • : By symmetry the line through perpendicular to must be orthogonal to the axis . • : Therefore is a radius. • : Also by symmetry, will bisect the arc . •
The axis and distance of a hypercycle are uniquely determined. • : Let us assume that a hypercycle has two different axes . • : Using the previous property twice with different chords we can determine two distinct radii . will then have to be perpendicular to both , giving us a rectangle. This is a contradiction because the rectangle is an impossible figure in
hyperbolic geometry. •
Two hypercycles have equal distances if and only if they are congruent. • : If they have equal distance, we just need to bring the axes to coincide by a rigid motion and also all the radii will coincide; since the distance is the same, also the points of the two hypercycles will coincide. • : Vice versa, if they are congruent the distance must be the same by the previous property. •
A straight line cuts a hypercycle in at most two points. • : Let the line cut the hypercycle in two points . As before, we can construct the radius of through the middle point of . Note that is
ultraparallel to the axis because they have the common perpendicular . Also, two ultraparallel lines have minimum distance at the common perpendicular and
monotonically increasing distances as we go away from the perpendicular. • : This means that the points of inside will have distance from smaller than the common distance of and from , while the points of outside will have greater distance. In conclusion, no other point of can be on . •
Two hypercycles intersect in at most two points. • : Let be hypercycles intersecting in three points . • : If is the line orthogonal to through its middle point, we know that it is a radius of both . • : Similarly we construct , the radius through the middle point of . • : are simultaneously orthogonal to the axes of , respectively. • : We already proved that then must coincide (otherwise we have a rectangle). • : Then have the same axis and at least one common point, therefore they have the same distance and they coincide. •
No three points of a hypercycle are collinear. • : If the points of a hypercycle are collinear then the chords are on the same line . Let be the radii through the middle points of . We know that the axis of the hypercycle is the common perpendicular of . • : But is that common
perpendicular. Then the distance must be 0 and the hypercycle degenerates into a line. == Other properties ==