Isosceles and equilateral triangles Let be a triangle center function. If two sides of a triangle are equal (say ) then \begin{align} f(a,b,c) &= f(b,a,c) &(\text{since }a = b)\\ &= f(b,c,a) & \text{(by bisymmetry)} \end{align} so two components of the associated triangle center are always equal. Therefore, all triangle centers of an isosceles triangle must lie on its
line of symmetry. For an equilateral triangle all three components are equal so all centers coincide with the centroid. So, like a circle, an equilateral triangle has a unique center.
Excenters Let f(a, b, c) = \begin{cases} -1 & \quad \text{if } a \ge b \text{ and } a \ge c, \\ \;\;\; 1 & \quad \text{otherwise}. \end{cases} This is readily seen to be a triangle center function and (provided the triangle is scalene) the corresponding triangle center is the excenter opposite to the largest vertex angle. The other two excenters can be picked out by similar functions. However, as indicated above only one of the excenters of an isosceles triangle and none of the excenters of an equilateral triangle can ever be a triangle center.
Biantisymmetric functions A function is
biantisymmetric if f(a,b,c) = -f(a,c,b) \quad \text{for all} \quad a,b,c. If such a function is also non-zero and homogeneous it is easily seen that the mapping (a,b,c) \to f(a,b,c)^2 \, f(b,c,a) \, f(c,a,b) is a triangle center function. The corresponding triangle center is f(a,b,c) : f(b,c,a) : f(c,a,b). On account of this the definition of triangle center function is sometimes taken to include non-zero homogeneous biantisymmetric functions.
New centers from old Any triangle center function can be
normalized by multiplying it by a
symmetric function of so that . A normalized triangle center function has the same triangle center as the original, and also the stronger property that f(ta,tb,tc) = f(a,b,c) \quad \text{for all} \quad t > 0, \ (a,b,c). Together with the zero function, normalized triangle center functions form an
algebra under addition, subtraction, and multiplication. This gives an easy way to create new triangle centers. However distinct normalized triangle center functions will often define the same triangle center, for example and (abc)^{-1}(a+b+c)^3 f.
Uninteresting centers Assume are real variables and let be any three real constants. Let f(a, b, c) = \begin{cases} \alpha & \quad \text{if } a b \text{ and } a > c & (a \text{ is greatest}), \\[2pt] \beta & \quad \text{otherwise} & (a \text{ is in the middle}). \end{cases} Then is a triangle center function and is the corresponding triangle center whenever the sides of the reference triangle are labelled so that . Thus every point is potentially a triangle center. However, the vast majority of triangle centers are of little interest, just as most continuous functions are of little interest.
Barycentric coordinates If is a triangle center function then so is and the corresponding triangle center is a \, f(a,b,c) : b \, f(b,c,a) : c \, f(c,a,b). Since these are precisely the
barycentric coordinates of the triangle center corresponding to it follows that triangle centers could equally well have been defined in terms of barycentrics instead of trilinears. In practice it isn't difficult to switch from one
coordinate system to the other.
Binary systems There are other center pairs besides the Fermat point and the 1st isogonic center. Another system is formed by
X3 and the incenter of the
tangential triangle. Consider the triangle center function given by: f(a, b, c) = \begin{cases} \cos A & \text{if } \triangle \text{ is acute}, \\[2pt] \cos A + \sec B \sec C & \text{if } \measuredangle A \text{ is obtuse}, \\[2pt] \cos A - \sec A & \text{if either} \measuredangle B \text{ or } \measuredangle C \text{ is obtuse}. \end{cases} For the corresponding triangle center there are four distinct possibilities: \begin{align} & \text{if reference } \triangle \text{ is acute:} \quad \cos A \ :\, \cos B \ :\, \cos C \\[6pt] & \begin{array}{rcccc} \text{if } \measuredangle A \text{ is obtuse:} & \cos A + \sec B \sec C &:& \cos B - \sec B &:& \cos C - \sec C \\[4pt] \text{if } \measuredangle B \text{ is obtuse:} & \cos A - \sec A &:& \cos B + \sec C \sec A &:& \cos C - \sec C \\[4pt] \text{if } \measuredangle C \text{ is obtuse:} & \cos A - \sec A &:& \cos B - \sec B &:& \cos C + \sec A \sec B \end{array}\end{align} Note that the first is also the circumcenter. Routine calculation shows that in every case these trilinears represent the incenter of the tangential triangle. So this point is a triangle center that is a close companion of the circumcenter.
Bisymmetry and invariance Reflecting a triangle reverses the order of its sides. In the image the coordinates refer to the triangle and (using "|" as the separator) the reflection of an arbitrary point \gamma : \beta : \alpha is \gamma\ |\ \beta \ |\ \alpha. If is a triangle center function the reflection of its triangle center is f(c,a,b)\ |\ f(b,c,a)\ |\ f(a,b,c), which, by bisymmetry, is the same as f(c,b,a)\ |\ f(b,a,c)\ |\ f(a,c,b). As this is also the triangle center corresponding to relative to the triangle, bisymmetry ensures that all triangle centers are invariant under reflection. Since rotations and translations may be regarded as double reflections they too must preserve triangle centers. These invariance properties provide justification for the definition.
Alternative terminology Some other names for dilation are
uniform scaling,
isotropic scaling,
homothety, and
homothecy. == Non-Euclidean and other geometries ==