For an incident unpolarized photon of energy E_\gamma, the
differential cross section is: : \frac{d\sigma}{d\Omega} = \frac{1}{2} r_e^2 \left(\frac{\lambda}{\lambda'}\right)^{2} \left[\frac{\lambda}{\lambda'} + \frac{\lambda'}{\lambda} - \sin^2(\theta)\right] where • r_e is the
classical electron radius (~2.82
fm, r_e^2 is about 7.94 × 10−30 m2 or 79.4
mb) • \lambda/\lambda' is the ratio of the wavelengths of the incident and scattered photons • \theta is the scattering angle (0 for an undeflected photon). The angular dependent photon wavelength (or energy, or frequency) ratio is : \frac{\lambda}{\lambda'} = \frac{E_{\gamma'}}{E_\gamma} = \frac{\omega'}{\omega} = \frac{1}{1 + \epsilon(1-\cos\theta)} as required by the conservation of
relativistic energy and momentum (see
Compton scattering). The dimensionless quantity \epsilon = E_\gamma/m_e c^2 expresses the energy of the incident photon in terms of the electron rest energy (~511
keV), and may also be expressed as \epsilon = \lambda_c/\lambda , where \lambda_c = h/m_e c is the
Compton wavelength of the electron (~2.42 pm). Notice that the scatter ratio \lambda'/\lambda increases
monotonically with the deflection angle, from 1 (forward scattering, no energy transfer) to 1+2\epsilon (180 degree backscatter, maximum energy transfer). In some cases it is convenient to express the classical electron radius in terms of the Compton wavelength: r_e=\alpha \bar\lambda_c = \alpha \lambda_c/2\pi, where \alpha is the
fine structure constant (~1/137) and \bar\lambda_c=\hbar/m_e c is the
reduced Compton wavelength of the electron (~0.386 pm), so that the constant in the cross section may be given as: : \frac{1}{2}r_e^2 = \frac{1}{2}\alpha^2\bar\lambda_c^2 = \frac{\alpha^2\lambda_c^2}{8\pi^2} = \frac{\alpha^2\hbar^2}{2m_e^2c^2} == Polarized photons ==