For a
Lebesgue integrable real or complex-valued function
f on
Rn, the indefinite integral is a
set function which maps a measurable set
A to the Lebesgue integral of f \cdot \mathbf{1}_A, where \mathbf{1}_{A} denotes the
characteristic function of the set
A. It is usually written A \mapsto \int_{A} f\ \mathrm{d}\lambda, with
λ the
n–dimensional
Lebesgue measure. The
derivative of this integral at
x is defined to be \lim_{B \to x} \frac{1} \int_{B}f \, \mathrm{d}\lambda, where |
B| denotes the volume (i.e., the Lebesgue measure) of a
ball B centered at
x, and
B →
x means that the diameter of
B tends to 0. The
Lebesgue differentiation theorem states that this derivative exists and is equal to
f(
x) at
almost every point
x ∈
Rn. In fact a slightly stronger statement is true. Note that: \left|\frac{1} \int_{B}f(y) \, \mathrm{d}\lambda(y) - f(x)\right| = \left|\frac{1} \int_{B}(f(y) - f(x))\, \mathrm{d}\lambda(y)\right| \le \frac{1} \int_{B}|f(y) -f(x)|\, \mathrm{d}\lambda(y). The stronger assertion is that the right hand side tends to zero for almost every point
x. The points
x for which this is true are called the
Lebesgue points of
f. A more general version also holds. One may replace the balls
B by a family \mathcal{V} of sets
U of
bounded eccentricity. This means that there exists some fixed
c > 0 such that each set
U from the family is contained in a ball
B with |U| \ge c \, |B|. It is also assumed that every point
x ∈
Rn is contained in arbitrarily small sets from \mathcal{V}. When these sets shrink to
x, the same result holds: for almost every point
x, f(x) = \lim_{U \to x, \, U \in \mathcal{V}} \frac{1} \int_U f \, \mathrm{d}\lambda. The family of cubes is an example of such a family \mathcal{V}, as is the family \mathcal{V}(
m) of rectangles in
R2 such that the ratio of sides stays between
m−1 and
m, for some fixed
m ≥ 1. If an arbitrary norm is given on
Rn, the family of balls for the metric associated to the norm is another example. The one-dimensional case was proved earlier by . If
f is integrable on the real line, the function F(x) = \int_{(-\infty,x]} f(t) \, \mathrm{d} t is almost everywhere differentiable, with F'(x) = f(x). Were F defined by a
Riemann integral this would be essentially the
fundamental theorem of calculus, but Lebesgue proved that it remains true when using the Lebesgue integral. ==Proof==