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Location parameter

In statistics, a location parameter of a probability distribution is a scalar- or vector-valued parameter , which determines the "location" or shift of the distribution. In the literature of location parameter estimation, the probability distributions with such parameter are found to be formally defined in one of the following equivalent ways:either as having a probability density function or probability mass function ; or having a cumulative distribution function ; or being defined as resulting from the random variable transformation , where is a random variable with a certain, possibly unknown, distribution. See also § Additive noise.

Definition
Source: Let f(x) be any probability density function and let \mu and \sigma > 0 be any given constants. Then the function g(x| \mu, \sigma)= \frac{1}{\sigma} f{\left(\frac{x-\mu}{\sigma}\right)} is a probability density function. The location family is then defined as follows: Let f(x) be any probability density function. Then the family of probability density functions \mathcal{F} = \{f(x-\mu) : \mu \in \mathbb{R}\} is called the location family with standard probability density function f(x) , where \mu is called the location parameter for the family. ==Additive noise==
Additive noise
An alternative way of thinking of location families is through the concept of additive noise. If x_0 is a constant and W is random noise with probability density f_W(w), then X = x_0 + W has probability density f_{x_0}(x) = f_W(x-x_0) and its distribution is therefore part of a location family. ==Proofs==
Proofs
For the continuous univariate case, consider a probability density function f(x | \theta), x \in [a, b] \subset \mathbb{R}, where \theta is a vector of parameters. A location parameter x_0 can be added by defining: g(x | \theta, x_0) = f(x - x_0 | \theta), \; x \in [a + x_0, b + x_0] it can be proved that g is a p.d.f. by verifying if it respects the two conditions g(x | \theta, x_0) \ge 0 and \int_{-\infty}^{\infty} g(x | \theta, x_0) dx = 1. g integrates to 1 because: \int_{-\infty}^{\infty} g(x | \theta, x_0) dx = \int_{a + x_0}^{b + x_0} g(x | \theta, x_0) dx = \int_{a + x_0}^{b + x_0} f(x - x_0 | \theta) dx now making the variable change u = x - x_0 and updating the integration interval accordingly yields: \int_{a}^{b} f(u | \theta) du = 1 because f(x | \theta) is a p.d.f. by hypothesis. g(x | \theta, x_0) \ge 0 follows from g sharing the same image of f, which is a p.d.f. so its range is contained in [0, 1]. ==See also==
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