As ionized material follows the Sun's magnetic field lines, due to the effect of magnetic field lines being frozen in the
plasma, the charged particles feel a force \mathbf{F} of the magnitude: : \mathbf{F}=q \mathbf{v} \times \mathbf{B} where q is the charge, \mathbf{v} is the velocity and \mathbf{B} is the magnetic field vector. This bending action forces the particles to "corkscrew" around the magnetic field lines while held in place by a
magnetic pressure or energy density P_B , while rotating together with the Sun as a solid body: :P_B=\frac{B^2}{2 \mu_0} Since magnetic field strength decreases with the cube of the distance there will be a distance from the star where the kinetic gas pressure P_g of the ionized gas is great enough to break away from the field lines: : P_g=n m v^2 where n is the number of particles, m is the mass of the individual particle and v is the radial velocity away from the Sun, or the speed of the solar wind. Due to the high conductivity of the stellar wind, the magnetic field outside the sun declines with radius like the mass density of the wind, i.e. as an inverse square law. The magnetic field is therefore given by : B(r)=B_s \frac{R^2}{r^2} where B_s is the magnetic field on the surface of the Sun and R is its radius. The critical distance where the material will break away from the field lines can then be calculated as the distance where the kinetic pressure and the magnetic pressure are equal, i.e.P_{B}=P_{g} \implies \frac{B(r_c)^2}{2\mu_0}=\frac{B_{s}^2R^4}{2\mu_{0}r^4_{c}}=nmv^2If the solar mass loss is isotropic then the mass loss becomes n m= \frac{dM/dt}{4\pi r^2 v}; plugging this into the above equation and isolating the critical radius it follows that the
Alfvén radius is given by :r_c=R \left(\frac{2\pi B_s^2 R^2}{\mu_0 v \dot{M}}\right)^{1 \over 2}
Current solar value It is estimated that: • The mass loss rate of the Sun due to its stellar wind is about \dot{M_{\odot}}=dM_{\odot}/dt = 2\cdot 10^{-14} M_{\odot}/\text{yr} \approx 1.2 \cdot 10^9 \, \rm kg/s • The solar wind speed is v=5\cdot10^5 \, \rm m/s • The magnetic field on the surface is B_s \approx 10^{-4} \rm T • The solar radius is R = 7 \cdot 10^5 \, \rm km This leads to a critical radius r_c =15 R_\odot. This means that the ionized plasma will rotate together with the Sun as a solid body until it reaches a distance of nearly 15 times the radius of the Sun; from there the material will break off and stop affecting the Sun. The amount of solar mass needed to be thrown out along the field lines to make the Sun completely stop rotating can then be calculated using the
specific angular momentum: :\frac{j_\odot}{j_c}=\left(\frac{R_\odot}{r_c}\right)^2 \approx 0.5\% It has been suggested that the Sun lost a comparable amount of material over the course of its lifetime. ==Weakened magnetic braking==