The projection transforms from latitude and longitude to map coordinates
x and
y via the following equations: :\begin{align} x &= R \frac{2 \sqrt 2}{\pi} \left( \lambda - \lambda_{0} \right) \cos \theta, \\[5px] y &= R \sqrt 2 \sin \theta ,\end{align} where
θ is an auxiliary angle defined by :2\theta + \sin 2\theta = \pi \sin \varphi \qquad (1) and
λ is the longitude,
λ is the central meridian,
φ is the latitude, and
R is the radius of the globe to be projected. The map has area 4
R, conforming to the surface area of the generating globe. The
x-coordinate has a range of [−2
R, 2
R], and the
y-coordinate has a range of [−
R,
R]. Equation (1) may be solved with rapid convergence (but slow near the poles) using
Newton–Raphson iteration: If
φ = ±, then also
θ = ±. In that case the iteration should be bypassed; otherwise,
division by zero may result. There exists a
closed-form inverse transformation: :\begin{align} \varphi &= \arcsin \frac{2 \theta + \sin 2\theta}{\pi}, \\[5px] \lambda &= \lambda_{0} + \frac{\pi x}{2 R \sqrt{2} \cos \theta}, \end{align} where
θ can be found by the relation :\theta = \arcsin \frac{y}{R \sqrt{2}}. \, The inverse transformations allow one to find the latitude and longitude corresponding to the map coordinates
x and
y. ==Alterations==