Because in a planar triangle \tfrac12\gamma = \tfrac12\pi - \tfrac12(\alpha + \beta), these identities can alternately be written in a form in which they are more clearly a limiting case of
Napier's analogies for spherical triangles (this was the form used by Von Oppel), : \begin{align} \frac{a + b} c &= \frac {\cos\tfrac12(\alpha - \beta)} {\cos\tfrac12(\alpha + \beta)}, \\[10mu] \frac{a - b} c &= \frac {\sin\tfrac12(\alpha - \beta)} {\sin\tfrac12(\alpha + \beta)}. \end{align} Dividing one by the other to eliminate c results in the
law of tangents, : \begin{align} \frac{a + b}{a - b} = \frac {\tan\tfrac12(\alpha + \beta)} {\tan\tfrac12(\alpha - \beta)}. \end{align} In terms of half-angle tangents alone, Mollweide's formula can be written as : \begin{align} \frac{a + b} c &= \frac {1 + \tan\tfrac12\alpha\,\tan\tfrac12\beta} {1 - \tan\tfrac12\alpha\,\tan\tfrac12\beta}, \\[10mu] \frac{a - b} c &= \frac {\tan\tfrac12\alpha - \tan\tfrac12\beta} {\tan\tfrac12\alpha + \tan\tfrac12\beta}, \end{align} or equivalently : \begin{align} \tan\tfrac12\alpha\,\tan\tfrac12\beta &= \frac {a + b - c} {a + b + c}, \\[10mu] \frac {\tan\tfrac12\alpha} {\tan\tfrac12\beta} &= \frac {\phantom{-}a - b + c} {-a + b + c}. \end{align} Multiplying the respective sides of these identities gives one half-angle tangent in terms of the three sides, : \bigl({\tan\tfrac12\alpha}\bigr)^2 = \frac {(a + b - c)(a - b + c)} {(a + b + c)(-a + b + c)}. which becomes the
law of cotangents after taking the square root, : \frac {\cot\tfrac12\alpha} {s - a} = \frac {\cot\tfrac12\beta} {s - b} = \frac {\cot\tfrac12\gamma} {s - c} = \sqrt{\frac {s\vphantom{)}} {(s - c)(s - b)(s - a)}}=\frac{1}{r}, where s = \tfrac12(a + b + c) is the
semiperimeter and r the
incircle radius. The identities can also be proven equivalent to the
law of sines and
law of cosines. == Dual relations ==