The construction of the Nicolosi globular projection is fairly simple with compasses and straightedge. Given a bounding circle to fit the map into, the poles are placed at the top and bottom of the circle, and the central meridian of the desired hemisphere is drawn as a straight vertical diameter between them. The equator is drawn as a straight horizontal diameter. Each remaining meridian is drawn as a circular arc going through both poles and the equator, such that meridians are equally spaced along the equator. Each remaining parallel is also drawn as a circular arc from the left edge through the central meridian to the right edge of the circle, such that the parallels are equally spaced around the perimeter of the circle and also equally spaced along the central meridian. A hemisphere shown with the Nicolosi globular projection closely resembles a hemisphere shown with the
azimuthal equidistant projection centered on the same point. In both projections of that hemisphere, the meridians are equally spaced along the equator, and the parallels are equally spaced along the central meridian and also equally spaced along the perimeter of the circle. :\begin{align} b &= \frac{\pi}{2 \left(\lambda-\lambda_0 \right)} - \frac{2 \left(\lambda - \lambda_0 \right)}{\pi} \\ c &= \frac{2 \varphi}{\pi} \\ d &= \frac{1 - c^2}{\sin \varphi - c} \\ M &= \frac{\frac{b \sin \varphi}{d} - \frac{b}{2}}{1+\frac{b^2}{d^2}} \\ N &= \frac{\frac{d^2 \sin \varphi}{b^2} + \frac{d}{2}}{1+\frac{d^2}{b^2}} \\ x &= \frac{\pi}{2} R \left(M \pm \sqrt{M^2 + \frac{\cos^2 \varphi}{1 + \frac{b^2}{d^2}}}\right) \\ y &= \frac{\pi}{2} R \left(N \pm \sqrt{N^2 - \frac{\frac{d^2}{b^2}\sin^2 \varphi + d \sin \varphi - 1}{1 + \frac{d^2}{b^2}}} \right) \end{align} Here, \varphi is the latitude, \lambda is the longitude, \lambda_0 is the central longitude for the hemisphere, and R is the radius of the globe to be projected. In the formula for x, the \pm sign takes the sign of \lambda-\lambda_0, i.e. take the positive root if \lambda-\lambda_0 is positive, or the negative root if \lambda-\lambda_0 is negative. In the formula for y, the \pm sign takes the opposite sign of \varphi, i.e. take the positive root if \varphi is negative, or the negative root if \varphi is positive. Under certain circumstances, the full formulae fail. Use the following formulae instead: When \lambda-\lambda_0 = 0, :\begin{align} x &= 0 \\ y &= R \varphi \end{align} When \varphi = 0, :\begin{align} x &= R \left(\lambda - \lambda_0 \right) \\ y &= 0 \end{align} When |\lambda - \lambda_0| = \frac{\pi}{2}, :\begin{align} x &= R \left(\lambda - \lambda_0 \right) \cos \varphi \\ y &= \frac{\pi}{2} R \sin \varphi \end{align} When |\varphi| = \frac{\pi}{2}, :\begin{align} x &= 0 \\ y &= R \varphi \end{align} ==See also==