Optical activity occurs due to molecules dissolved in a fluid or due to the fluid itself only if the molecules are one of two (or more)
stereoisomers; this is known as an
enantiomer. The structure of such a molecule is such that it is
not identical to its
mirror image (which would be that of a different stereoisomer, or the "opposite enantiomer"). In mathematics, this property is also known as
chirality. For instance, a metal rod is
not chiral, since its appearance in a mirror is not distinct from itself. However a screw or light bulb base (or any sort of
helix)
is chiral; an ordinary right-handed screw thread, viewed in a mirror, would appear as a left-handed screw (very uncommon) which could not possibly screw into an ordinary (right-handed) nut. A human viewed in a mirror would have their heart on the right side, clear evidence of chirality, whereas the mirror reflection of a doll might well be indistinguishable from the doll itself. In order to display optical activity, a fluid must contain only one, or a preponderance of one, stereoisomer. If two enantiomers are present in equal proportions, then their effects cancel out and no optical activity is observed; this is termed a
racemic mixture. But when there is an
enantiomeric excess, more of one enantiomer than the other, the cancellation is incomplete and optical activity is observed. Many naturally occurring molecules are present as only one enantiomer (such as many sugars). Chiral molecules produced within the fields of
organic chemistry or
inorganic chemistry are racemic unless a chiral reagent was employed in the same reaction. At the fundamental level, polarization rotation in an optically active medium is caused by circular birefringence, and can best be understood in that way. Whereas
linear birefringence in a crystal involves a small difference in the
phase velocity of light of two different linear polarizations, circular birefringence implies a small difference in the velocities between right and left-handed
circular polarizations. The familiar rotation of the axis of
linear polarization relies on the understanding that a linearly polarized wave can as well be described as the
superposition (addition) of a left and right circularly polarized wave in equal proportion. The phase difference between these two waves is dependent on the orientation of the linear polarization which we'll call \theta_0, and their electric fields have a relative phase difference of 2\theta_0 which then add to produce linear polarization: : \mathbf{E}_{\theta_0} = \frac{\sqrt{2}}{2} \big(e^{-i\theta_0} \mathbf{E}_\text{RHC} + e^{i\theta_0} \mathbf{E}_\text{LHC}\big), where \mathbf{E}_{\theta_0} is the
electric field of the net wave, while \mathbf{E}_\text{RHC} and \mathbf{E}_\text{LHC} are the two circularly polarized
basis functions (having zero phase difference). Assuming propagation in the +
z direction, we could write \mathbf{E}_\text{RHC} and \mathbf{E}_\text{LHC} in terms of their
x and
y components as follows: : \mathbf{E}_\text{RHC} = \frac{\sqrt{2}}{2} (\hat{x} + i \hat{y}), : \mathbf{E}_\text{LHC} = \frac{\sqrt{2}}{2} (\hat{x} - i \hat{y}), where \hat{x} and \hat{y} are unit vectors, and
i is the
imaginary unit, in this case representing the 90-degree phase shift between the
x and
y components that we have decomposed each circular polarization into. As usual when dealing with
phasor notation, it is understood that such quantities are to be multiplied by e^{-i\omega t} and then the actual electric field at any instant is given by the
real part of that product. Substituting these expressions for \mathbf{E}_\text{RHC} and \mathbf{E}_\text{LHC} into the equation for \mathbf{E}_{\theta_0}, we obtain : \begin{align} \mathbf{E}_{\theta_0} &= \frac{\sqrt{2}}{2} \big(e^{-i\theta_0} \mathbf{E}_\text{RHC} + e^{i\theta_0} \mathbf{E}_\text{LHC}\big) \\ &= \frac{1}{2} \big[\hat{x} \big(e^{-i\theta_0} + e^{i\theta_0}\big) + \hat{y} i \big(e^{-i\theta_0} - e^{i\theta_0}\big)\big] \\ &= \hat{x} \cos\theta_0 + \hat{y} \sin\theta_0. \end{align} The last equation shows that the resulting vector has the
x and
y components in phase and oriented exactly in the \theta_0 direction, as we had intended, justifying the representation of any linearly polarized state at angle \theta as the superposition of right and left circularly polarized components with a relative phase difference of 2\theta. Now let us assume transmission through an optically active material which induces an additional phase difference between the right and left circularly polarized waves of 2\Delta \theta. Let us call \mathbf{E}_\text{out} the result of passing the original wave linearly polarized at angle \theta through this medium. This will apply additional phase factors of -\Delta \theta and \Delta \theta to the right and left circularly polarized components of \mathbf{E}_{\theta_0}: : \mathbf{E}_\text{out} = \frac{\sqrt{2}}{2} \big(e^{-i\Delta\theta} e^{-i\theta_0} \mathbf{E}_\text{RHC} + e^{i\Delta\theta} e^{i\theta_0} \mathbf{E}_\text{LHC}\big). Using similar math as above, we find : \mathbf{E}_\text{out} = \hat{x} \cos(\theta_0 + \Delta\theta) + \hat{y} \sin(\theta_0 + \Delta\theta), describing a wave linearly polarized at angle \theta_0 + \Delta\theta, thus rotated by \Delta\theta relative to the incoming wave \mathbf{E}_{\theta_0}. We defined above the difference in the refractive indices for right and left circularly polarized waves of \Delta n. Considering propagation through a length
L in such a material, there will be an additional phase difference induced between them of 2\Delta \theta (as we used above) given by : 2\Delta \theta = \frac{\Delta n L2\pi}{\lambda}, where \lambda is the wavelength of the light (in vacuum). This will cause a rotation of the linear axis of polarization by \Delta \theta as we have shown. In general, the refractive index depends on wavelength (see
dispersion) and the differential refractive index \Delta n will also be wavelength dependent. The resulting variation in rotation with the wavelength of the light is called
optical rotatory dispersion (ORD). ORD spectra and
circular dichroism spectra are related through the
Kramers–Kronig relations. Complete knowledge of one spectrum allows the calculation of the other. So we find that the degree of rotation depends on the color of the light (the yellow sodium D line near 589 nm
wavelength is commonly used for measurements) and is directly proportional to the path length L through the substance and the amount of circular birefringence of the material \Delta n which, for a solution, may be computed from the substance's
specific rotation and its concentration in solution. Although optical activity is normally thought of as a property of fluids, particularly
aqueous solutions, it has also been observed in crystals such as
quartz (SiO2). Although quartz has a substantial linear birefringence, that effect is cancelled when propagation is along the
optic axis. In that case, rotation of the plane of polarization is observed due to the relative rotation between crystal planes, thus making the crystal formally chiral as we have defined it above. The rotation of the crystal planes can be right or left-handed, again producing opposite optical activities. On the other hand,
amorphous forms of
silica such as
fused quartz, like a racemic mixture of chiral molecules, has no net optical activity since one or the other crystal structure does not dominate the substance's internal molecular structure. == Applications ==