The optional stopping theorem has widespread applications in probability, paradox resolution, and random walk theory: •
Impossibility of perfect betting strategies: The theorem can be used to prove the impossibility of successful betting strategies for a gambler with a finite lifetime (giving condition ()) or a house limit on bets (condition ()). • Suppose that the gambler can wager up to c dollars on a
fair coin flip at times 1, 2, 3, etc., winning their wager if the coin comes up heads and losing it if the coin comes up tails. • Suppose further that the gambler can quit whenever they like, but cannot predict the outcome of gambles that have not happened yet. • The gambler's fortune over time is a martingale, and the time \tau at which they decide to quit (or go broke and are forced to quit) is a stopping time. So the theorem says that \mathbb{E}[X_{\tau}]=\mathbb{E}[X_0]. In other words, the gambler leaves with the same amount of money
on average as when they started. • The same result holds if the gambler has a finite limit on their line of credit or how far in debt they may go, rather than a house limit on individual bets. •
Expected stop position of a random walk: Suppose a
random walk starting at a\ge 0 goes up or down by one with equal probability on each step. • Suppose further that the walk stops if it reaches 0 or m\ge a; the time at which this first occurs is a stopping time. • If it is known that the expected time at which the walk ends is finite (e.g., from
Markov chain theory), the optional stopping theorem predicts that the expected stop position is equal to the initial position a. • Solving a=pm+(1-p)0 for the probability p that the walk reaches m before 0 gives p=a/m. •
Expected time of a random walk: Consider a random walk X that starts at 0 and stops if it reaches -m or +m, and use the Y_n=X_n^2-n martingale from . If \tau is the time at which X first reaches \pm m, then 0=\mathbb{E}[Y_0]=\mathbb{E}[Y_\tau]=m^2-\mathbb{E}[\tau]. This directly gives \mathbb{E}[\tau]=m^2. •
Violations of the theorem (Counterexamples): Care must be taken to ensure that one of the conditions of the theorem holds. • For example, suppose the last example had instead used a 'one-sided' stopping time, so that stopping only occurred at +m, not at -m. • The value of X at this stopping time would therefore be m, meaning the expectation value \mathbb{E}[X_\tau] must also be m. • This seemingly violates the theorem which would give \mathbb{E}[X_\tau]=X_0=0. The failure of the optional stopping theorem in this case shows that all three of the conditions fail for a one-sided stopping time with an unrestricted state space. == Proof ==