The largest number that always divides the product is 12. The quadruple with the minimal product is (1, 2, 2, 3). Given a Pythagorean quadruple (a,b,c,d) where d^2=a^2+b^2+c^2 then d can be defined as the norm of the quadruple in that d = \sqrt{a^2+b^2+c^2} and is analogous to the hypotenuse of a Pythagorean triple. Of the 3 terms within a primitive Pythagorean quadruple that are not the norm, exactly one will always be odd and the other two will be even. Consequently, the norm has to be odd. Every odd positive number other than 1 and 5 can be the norm of a primitive Pythagorean quadruple d^2=a^2+b^2+c^2 such that a, b, c are greater than zero and are coprime. All primitive Pythagorean quadruples with the odd numbers as norms up to 29 except 1 and 5 are given in the table below. Similar to a Pythagorean triple which generates a distinct right triangle, a Pythagorean quadruple will generate a distinct
Heronian triangle. If is a Pythagorean quadruple with a^2 + b^2 + c^2 = d^2 it will generate a Heronian triangle with sides as follows: \begin{align} x &= d^2 - a^2 \\ y &= d^2 - b^2 \\ z &= d^2 - c^2 \end{align} It will have a semiperimeter s = d^2, an area A = abcd and an inradius r = abc/d. The exradii will be: \begin{align} r_x &= bcd/a, \\ r_y &= acd/b, \\ r_z &= abd/c. \end{align} The
circumradius will be: R = \frac{(d^2 - a^2)(d^2 - b^2)(d^2 - c^2)}{4abcd} = \frac{abcd(1/a^2 + 1/b^2 + 1/c^2 -1/d^2)}{4} The ordered sequence of areas of this class of Heronian triangles can be found at . ==Relationship with quaternions and rational orthogonal matrices==