offers a straightforward way to present orthogonal states. With a typical mapping ^2 and the probability of outcome ^2. Because the absolute squares of the amplitudes equate to probabilities, it follows that \alpha and \beta must be constrained according to the
second axiom of probability theory by the equation : ^2 + ^2 = 1. The probability amplitudes, \alpha and \beta, encode more than just the probabilities of the outcomes of a measurement; the
relative phase between \alpha and \beta is, for example, responsible for
quantum interference, as seen in the
double-slit experiment.
Bloch sphere representation The
probability amplitudes for the superposition state, ^2 = 1.Note that by removing e^{i\delta} it means that
quantum states with global phase can not be represented as points on the surface of the Bloch sphere.}} so we can arbitrarily choose to be real (or in the case that is zero), leaving just two degrees of freedom: :\begin{align} \alpha &= \cos\frac{\theta}{2}, \\ \beta &= e^{i \varphi} \sin\frac{\theta}{2}, \end{align} where e^{i \varphi} is the physically significant
relative phase.{{efn|The Pauli Z basis is usually called the
computational basis, where the relative phase have no effect on measurement.
Measuring instead in the X or Y Pauli basis depends on the relative phase. For example, ({|0\rangle} + e^{i\pi/2}{|1\rangle})/{\sqrt{2}} will (because this state lies on the positive pole of the Y-axis) in the Y-basis always measure to the same value, while in the Z-basis results in equal probability of being measured to {|0\rangle} or {|1\rangle}.Because measurement
collapses the quantum state, measuring the state in one basis hides some of the values that would have been measurable in the other basis; See the
uncertainty principle.}} The possible quantum states for a single qubit can be visualised using a
Bloch sphere (see picture). Represented on such a
2-sphere, a classical bit could only be at the "North Pole" or the "South Pole", in the locations where {|0 \rangle} and {|1 \rangle} are respectively. This particular choice of the polar axis is arbitrary, however. The rest of the surface of the Bloch sphere is inaccessible to a classical bit, but a pure qubit state can be represented by any point on the surface. For example, the pure qubit state ({|0 \rangle} + {|1 \rangle})/{\sqrt{2}} would lie on the equator of the sphere at the positive X-axis. In the
classical limit, a qubit, which can have quantum states anywhere on the Bloch sphere, reduces to the classical bit, which can be found only at either poles. The surface of the Bloch sphere is a
two-dimensional space, which represents the observable
state space of the pure qubit states. This state space has two local degrees of freedom, which can be represented by the two angles \varphi and \theta.
Mixed state A pure state is fully specified by a single ket, {|\psi\rangle} = \alpha {|0\rangle} + \beta {|1\rangle},\, a coherent superposition, represented by a point on the surface of the Bloch sphere as described above. Coherence is essential for a qubit to be in a superposition state. With interactions,
quantum noise and
decoherence, it is possible to put the qubit in a
mixed state, a statistical combination or "incoherent mixture" of different pure states. Mixed states can be represented by points
inside the Bloch sphere (or in the Bloch ball). A mixed qubit state has three degrees of freedom: the angles \varphi and \theta , as well as the length r of the vector that represents the mixed state.
Quantum error correction can be used to maintain the purity of qubits. ==Operations on qubits==