In the context of the
quantum harmonic oscillator, one reinterprets the ladder operators as creation and annihilation operators, adding or subtracting fixed
quanta of energy to the oscillator system. Creation/annihilation operators are different for
bosons (integer spin) and
fermions (
half-integer spin). This is because their
wavefunctions have different
symmetry properties. First consider the simpler bosonic case of the photons of the quantum harmonic oscillator. Start with the
Schrödinger equation for the one-dimensional time independent
quantum harmonic oscillator, \left(-\frac{\hbar^2}{2m} \frac{d^2}{d x^2} + \frac{1}{2}m \omega^2 x^2\right) \psi(x) = E \psi(x). Make a coordinate substitution to
nondimensionalize the differential equation x \ = \ \sqrt{ \frac{\hbar}{m \omega}} q. The Schrödinger equation for the oscillator becomes \frac{\hbar \omega}{2} \left(-\frac{d^2}{d q^2} + q^2 \right) \psi(q) = E \psi(q). Note that the quantity \hbar \omega = h \nu is the same energy as that found for light
quanta and that the parenthesis in the
Hamiltonian can be written as -\frac{d^2}{dq^2} + q^2 = \left(-\frac{d}{dq}+q \right) \left(\frac{d}{dq}+ q \right) + \frac {d}{dq}q - q \frac {d}{dq} . The last two terms can be simplified by considering their effect on an arbitrary
differentiable function f(q), \left(\frac{d}{dq} q- q \frac{d}{dq} \right)f(q) = \frac{d}{dq}(q f(q)) - q \frac{df(q)}{dq} = f(q) which implies, \frac{d}{dq} q- q \frac{d}{dq} = 1 , coinciding with the usual canonical commutation relation -i[q,p]=1 , in position space representation: p:=-i\frac{d}{dq}. Therefore, -\frac{d^2}{dq^2} + q^2 = \left(-\frac{d}{dq}+q \right) \left(\frac{d}{dq}+ q \right) + 1 and the Schrödinger equation for the oscillator becomes, with substitution of the above and rearrangement of the factor of 1/2, \hbar \omega \left[\frac{1}{\sqrt{2}} \left(-\frac{d}{dq}+q \right)\frac{1}{\sqrt{2}} \left(\frac{d}{dq}+ q \right) + \frac{1}{2} \right] \psi(q) = E \psi(q). If one defines a^\dagger \ = \ \frac{1}{\sqrt{2}} \left(-\frac{d}{dq} + q\right) as the
"creation operator" or the
"raising operator" and a \ \ = \ \frac{1}{\sqrt{2}} \left(\frac{d}{dq} + q\right) as the
"annihilation operator" or the
"lowering operator", the Schrödinger equation for the oscillator reduces to \hbar \omega \left( a^\dagger a + \frac{1}{2} \right) \psi(q) = E \psi(q). This is significantly simpler than the original form. Further simplifications of this equation enable one to derive all the properties listed above thus far. Letting p = - i \frac{d}{dq}, where p is the nondimensionalized
momentum operator, one has [q, p] = i \, and \begin{align} a &= \frac{1}{\sqrt{2}}(q + i p) = \frac{1}{\sqrt{2}}\left( q + \frac{d}{dq}\right) \\[1ex] a^\dagger &= \frac{1}{\sqrt{2}}(q - i p) = \frac{1}{\sqrt{2}}\left( q - \frac{d}{dq}\right). \end{align} Note that these imply [a, a^\dagger ] = \frac{1}{2} [ q + ip , q-i p] = \frac{1}{2} ([q,-ip] + [ip, q]) = -\frac{i}{2} ([q, p] + [q, p]) = 1. The operators a\, and a^\dagger\, may be contrasted to
normal operators, which commute with their adjoints. Using the commutation relations given above, the Hamiltonian operator can be expressed as \hat H = \hbar \omega \left( a \, a^\dagger - \frac{1}{2}\right) = \hbar \omega \left( a^\dagger \, a + \frac{1}{2}\right).\qquad\qquad(*) One may compute the commutation relations between the a\, and a^\dagger\, operators and the Hamiltonian: \begin{align} \left[\hat H, a \right] &= \left[\hbar \omega \left ( a a^\dagger - \tfrac{1}{2}\right ) , a\right] = \hbar \omega \left[ a a^\dagger, a\right] = \hbar \omega \left( a [a^\dagger,a] + [a,a] a^\dagger\right) = -\hbar \omega a. \\[1ex] \left[\hat H, a^\dagger \right] &= \hbar \omega \, a^\dagger . \end{align} These relations can be used to easily find all the energy eigenstates of the quantum harmonic oscillator as follows. Assuming that \psi_n is an eigenstate of the Hamiltonian \hat H \psi_n = E_n\, \psi_n. Using these commutation relations, it follows that
Matrix representation The matrix expression of the creation and annihilation operators of the quantum harmonic oscillator with respect to the above orthonormal basis is \begin{align} a^\dagger &= \begin{pmatrix} 0 & 0 & 0 & 0 & \dots & 0 & \dots \\ \sqrt{1} & 0 & 0 & 0 & \dots & 0 & \dots \\ 0 & \sqrt{2} & 0 & 0 & \dots & 0 & \dots \\ 0 & 0 & \sqrt{3} & 0 & \dots & 0 & \dots \\ \vdots & \vdots & \vdots & \ddots & \ddots & \dots & \dots \\ 0 & 0 & 0 & \dots & \sqrt{n} & 0 & \dots & \\ \vdots & \vdots & \vdots & \vdots & \vdots & \ddots & \ddots \end{pmatrix} \\[1ex] a &= \begin{pmatrix} 0 & \sqrt{1} & 0 & 0 & \dots & 0 & \dots \\ 0 & 0 & \sqrt{2} & 0 & \dots & 0 & \dots \\ 0 & 0 & 0 & \sqrt{3} & \dots & 0 & \dots \\ 0 & 0 & 0 & 0 & \ddots & \vdots & \dots \\ \vdots & \vdots & \vdots & \vdots & \ddots & \sqrt{n} & \dots \\ 0 & 0 & 0 & 0 & \dots & 0 & \ddots \\ \vdots & \vdots & \vdots & \vdots & \vdots & \vdots & \ddots \end{pmatrix} \end{align} These can be obtained via the relationships a^\dagger_{ij} = \left\langle\psi_i \right| a^\dagger \left| \psi_j\right\rangle and a_{ij} = \left\langle\psi_i \right| a \left| \psi_j\right\rangle. The
eigenvectors \psi_i are those of the quantum harmonic oscillator, and are sometimes called the "number basis". == Generalized creation and annihilation operators ==