When comparing the frequency- and wavelength-dependent expressions of the Rayleigh–Jeans law, it is important to remember that \frac{dP}{d\lambda} = B_{\lambda}(T) and \frac{dP}{d\nu} = B_{\nu}(T). Note that these two expressions then have different units, as a step d\lambda in wavelength is not equivalent to a step d\nu in frequency. Therefore, B_{\lambda}(T) \neq B_{\nu}(T), even after substituting the value \lambda = c/\nu, because B_\lambda(T) has
units of energy emitted per unit time per unit area of emitting surface, per unit
solid angle,
per unit wavelength, whereas B_\nu(T) has units of energy emitted per unit time per unit area of emitting surface, per unit solid angle,
per unit frequency. To be consistent, we must use the equality B_\lambda \, d\lambda = dP = B_\nu \, d\nu, where both sides now have units of power (energy emitted per unit time) per unit area of emitting surface, per unit solid angle. Starting with the Rayleigh–Jeans law in terms of wavelength, we get B_\lambda(T) = B_\nu(T) \frac{d\nu}{d\lambda}, where \frac{d\nu}{d\lambda} = \frac{d}{d\lambda} \left(\frac{c}{\lambda}\right) = -\frac{c}{\lambda^2}. This leads to B_\lambda(T) = \frac{2k_\text{B} T\left(\frac{c}{\lambda}\right)^2}{c^2} \times \frac{c}{\lambda^2} = \frac{2ck_\text{B} T}{\lambda^4}. == Other forms of Rayleigh–Jeans law ==