Values at integral points A refinable function is defined only implicitly. It may also be that there are several functions which are refinable with respect to the same mask. If \varphi shall have finite support and the function values at integer arguments are wanted, then the two scale equation becomes a system of
simultaneous linear equations. Let a be the minimum index and b be the maximum index of non-zero elements of h, then one obtains \begin{pmatrix} \varphi(a)\\ \varphi(a+1)\\ \vdots\\ \varphi(b) \end{pmatrix} = \begin{pmatrix} h_{a } & & & & & \\ h_{a+2} & h_{a+1} & h_{a } & & & \\ h_{a+4} & h_{a+3} & h_{a+2} & h_{a+1} & h_{a } & \\ \ddots & \ddots & \ddots & \ddots & \ddots & \ddots \\ & h_{b } & h_{b-1} & h_{b-2} & h_{b-3} & h_{b-4} \\ & & & h_{b } & h_{b-1} & h_{b-2} \\ & & & & & h_{b } \end{pmatrix} \begin{pmatrix} \varphi(a)\\ \varphi(a+1)\\ \vdots\\ \varphi(b) \end{pmatrix}. Using the
discretization operator, call it Q here, and the
transfer matrix of h, named T_h, this can be written concisely as Q\varphi = T_h Q\varphi. This is again a
fixed-point equation. But this one can now be considered as an
eigenvector-
eigenvalue problem. That is, a finitely supported refinable function exists only (but not necessarily), if T_h has the eigenvalue 1.
Values at dyadic points From the values at integral points you can derive the values at dyadic points, i.e. points of the form k\cdot 2^{-j}, with k\in\Z and j\in\N. :\varphi = D_{1/2} (2\cdot (h * \varphi)) :D_2 \varphi = 2\cdot (h * \varphi) :Q(D_2 \varphi) = Q(2\cdot (h * \varphi)) = 2\cdot (h * Q\varphi) The star denotes the
convolution of a discrete filter with a function. With this step you can compute the values at points of the form \frac{k}{2}. By replacing iteratedly \varphi by D_2 \varphi you get the values at all finer scales. Q(D_{2^{j+1}}\varphi) = 2\cdot (h * Q(D_{2^j}\varphi))
Convolution If \varphi is refinable with respect to h, and \psi is refinable with respect to g, then \varphi*\psi is refinable with respect to h*g.
Differentiation If \varphi is refinable with respect to h, and the derivative \varphi' exists, then \varphi' is refinable with respect to 2\cdot h. This can be interpreted as a special case of the convolution property, where one of the convolution operands is a derivative of the
Dirac impulse.
Integration If \varphi is refinable with respect to h, and there is an antiderivative \Phi with \Phi(t) = \int_0^{t}\varphi(\tau)\,\mathrm{d}\tau, then the antiderivative t \mapsto \Phi(t) + c is refinable with respect to mask \frac{1}{2}\cdot h where the constant c must fulfill c\cdot \left(1 - \sum_j h_j\right) = \sum_j h_j \cdot \Phi(-j). If \varphi has
bounded support, then we can interpret integration as convolution with the
Heaviside function and apply the convolution law.
Scalar products Computing the scalar products of two refinable functions and their translates can be broken down to the two above properties. Let T be the translation operator. It holds \langle \varphi, T_k \psi\rangle = \langle \varphi * \psi^*, T_k\delta\rangle = (\varphi*\psi^*)(k) where \psi^* is the
adjoint of \psi with respect to
convolution, i.e., \psi^* is the flipped and
complex conjugated version of \psi, i.e., \psi^*(t) = \overline{\psi(-t)}. Because of the above property, \varphi*\psi^* is refinable with respect to h*g^*, and its values at integral arguments can be computed as eigenvectors of the transfer matrix. This idea can be easily generalized to integrals of products of more than two refinable functions.
Smoothness A refinable function usually has a fractal shape. The design of continuous or smooth refinable functions is not obvious. Before dealing with forcing smoothness it is necessary to measure smoothness of refinable functions. Using the Villemoes machine one can compute the smoothness of refinable functions in terms of
Sobolev exponents. In a first step the refinement mask h is divided into a filter b, which is a power of the smoothness factor (1,1) (this is a binomial mask) and a rest q. Roughly spoken, the binomial mask b makes smoothness and q represents a fractal component, which reduces smoothness again. Now the Sobolev exponent is roughly the order of b minus
logarithm of the
spectral radius of T_{q*q^*}. ==Generalization==