Reflections of signals on conducting lines typically exhibit a phase change from the incident signal. There are two extreme cases of termination: short circuit (closed line), and open circuit (broken line). In both cases the full amplitude of the wave is reflected. ;short circuit: The voltage wave reflection on a line terminated with a short circuit is 180° phase shifted. This is analogous (by the
mobility analogy) to a string where the end is fixed in position, or a sound wave in a tube with a blocked off end. The current wave, on the other hand, is not phase shifted. ;broken / open line: A
transmission line terminated with an open circuit is the
dual case; the voltage wave is shifted by 0° and the current wave is shifted by 180°. ;reactive termination: A transmission line terminated with a pure
capacitance or
inductance will also give rise to a phase shifted wave at full amplitude. The voltage phase shift is given by \varphi = 2 \tan ^{-1} {Z_0 \over X} where :*
Z0 is the
characteristic impedance of the line :*
X is the
reactance of the inductance or capacitance, given respectively by
ωL or :*
L and
C are, respectively, inductance and capacitance, and :*
ω is the
angular frequency. In the case of reactive termination the phase shift will be between 0 and +180° for
inductors and between 0 and −180° for
capacitors. The phase shift will be exactly ±90° when |
X| =
Z0. For the general case when the line is terminated with some arbitrary
impedance,
Z, the reflected wave is generally less than the incident wave. The full expression for phase shift needs to be used, \varphi = \tan ^{-1} \left ( \frac {2 \sin (\arg Z) }{ \left( \frac{Z_0} - \frac{Z_0} \right) } \right ) This expression assumes the characteristic impedance is purely
resistive. ==See also==