The simplest case of rolling is that of a
rigid body rolling without slipping along a flat surface with its axis parallel to the surface (or equivalently: perpendicular to the surface
normal). The trajectory of any point is a
trochoid; in particular, the trajectory of any point in the object axis is a line, while the trajectory of any point in the object rim is a
cycloid. The velocity of any point in the rolling object is given by \mathbf{v} = \boldsymbol{\omega}\times\mathbf{r}, where \mathbf{r} is the
displacement between the particle and the rolling object's contact point (or line) with the surface, and ω is the
angular velocity vector. Thus, despite that rolling is different from
rotation around a fixed axis, the
instantaneous velocity of all particles of the rolling object is the same as if it was rotating around an axis that passes through the point of contact with the same angular velocity. Any point in the rolling object farther from the axis than the point of contact will temporarily move opposite to the direction of the overall motion when it is below the level of the rolling surface (for example, any point in the part of the flange of a train wheel that is below the rail).
Energy Since
kinetic energy is entirely a function of an object mass and velocity, the above result may be used with the
parallel axis theorem to obtain the kinetic energy associated with simple rolling K_\text{rolling} = K_\text{translation} + K_\text{rotation}
Forces and acceleration Differentiating the relation between linear and angular
velocity, v_\text{c.o.m.} = r\omega, with respect to time gives a formula relating linear and angular
acceleration a = r\alpha. Applying
Newton's second law: a = \frac{F_\text{net}}{m} = r\alpha = \frac{r\tau}{I}. It follows that to accelerate the object, both a net force and a
torque are required. When external force with no torque acts on the rolling object‐surface system, there will be a tangential force at the point of contact between the surface and rolling object that provides the required torque as long as the motion is pure rolling; this force is usually
static friction, for example, between the road and a wheel or between a bowling lane and a bowling ball. When static friction isn't enough, the friction becomes
dynamic friction and slipping happens. The tangential force is opposite in direction to the external force, and therefore partially cancels it. The resulting
net force and acceleration are: \begin{align} F_\text{net} &= \frac{F_\text{external}}{1 + \frac{I}{mr^2}} = \frac{F_\text{external}}{1 + \left({r_\text{g}}/{r}\right)^2} \\[1ex] a &= \frac{F_\text{external}}{m + {I}/{r^2}} \end{align} \tfrac{I}{r^2} has dimension of mass, and it is the mass that would have a rotational inertia I at distance r from an axis of rotation. Therefore, the term \tfrac{I}{r^2} may be thought of as the mass with linear inertia equivalent to the rolling object rotational inertia (around its center of mass). The action of the external force upon an object in simple rotation may be conceptualized as accelerating the sum of the real mass and the virtual mass that represents the rotational inertia, which is m+\tfrac{I}{r^2}. Since the work done by the external force is split between overcoming the translational and rotational inertia, the external force results in a smaller net force by the
dimensionless multiplicative factor 1/\left(1+\tfrac{I}{mr^2}\right) where \tfrac{I}{mr^2} represents the ratio of the aforesaid virtual mass to the object actual mass and it is equal to \left({r_\text{g}}/{r}\right)^2 where r_\text{g} is the
radius of gyration corresponding to the object rotational inertia in pure rotation (not the rotational inertia in pure rolling). The square power is due to the fact rotational inertia of a point mass varies proportionally to the square of its distance to the axis. ,
animated GIF version. In the specific case of an object rolling in an
inclined plane which experiences only static friction,
normal force and its own weight, (
air drag is absent) the acceleration in the direction of rolling down the slope is: a = \frac{g\sin(\theta)}{1+\left({r_\text{g}}/{r}\right)^2} {r_\text{g}}/{r} is specific to the object shape and mass distribution, it does not depend on scale or density. However, it will vary if the object is made to roll with different radiuses; for instance, it varies between a train wheel set rolling normally (by its tire), and by its axle. It follows that given a reference rolling object, another object bigger or with different density will roll with the same acceleration. This behavior is the same as that of an object in free fall or an object sliding without friction (instead of rolling) down an inclined plane. == Deformable bodies ==