===
n=1 Ligand=== When each receptor has a single ligand
binding site, the system is described by : [R] + [L] \underset{k_{\text{off}}}{\overset{k_{\text{on}}}{\rightleftharpoons}} [RL] with an on-rate (
kon) and off-rate (
koff) related to the dissociation constant through
Kd=
koff/
kon. When the system equilibrates, : k_{\text{on}} [R] [L] = k_{\text{off}} [RL] so that the average number of ligands bound to each receptor is given by : \bar{n} = \frac{[RL]}{[R] + [RL]} = \frac{[L]}{K_d + [L]} = (1 - \bar{n}) \frac{[L]}{K_d} which is the Scatchard equation for
n=1. ===
n=2 Ligands=== When each receptor has two ligand binding sites, the system is governed by : [R] + [L] \underset{k_{\text{off}}}{\overset{2k_{\text{on}}}{\rightleftharpoons}} [RL] : [RL] + [L] \underset{2k_{\text{off}}}{\overset{k_{\text{on}}}{\rightleftharpoons}} [RL_2]. At equilibrium, the average number of ligands bound to each receptor is given by : \bar{n} = \frac{[RL] + 2[RL_2]}{[R] + [RL] + [RL_2]} = \frac{2\frac{[L]}{K_d} + 2 \left( \frac{[L]}{K_d} \right)^2}{\left( 1 + \frac{[L]}{K_d} \right)^2} = \frac{2[L]}{K_d + [L]} = (2 - \bar{n}) \frac{[L]}{K_d} which is equivalent to the Scatchard equation.
General Case of n Ligands For a receptor with
n binding sites that independently bind to the ligand, each binding site will have an average occupancy of [
L]/(
Kd + [
L]). Hence, by considering all
n binding sites, there will : \bar{n} = n \frac{[L]}{K_d + [L]} = (n - \bar{n}) \frac{[L]}{K_d}. ligands bound to each receptor on average, from which the Scatchard equation follows. ==Problems with the method==